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2006 Nov 17
0
difftime for handling time units--hours, minutes, days--from file times
Thanks, Tim
To get the time difference in the proper units, it's as simple as this:
difftime(myfileinfo$mtime[2], myfileinfo$mtime[1], units="hours")
Cheers,
Warren
On 11/13/06, Tim Calkins <tcalkins@gmail.com> wrote:
> hardly the most efficient way to go, but consider using a substring
> function to extract the time bits from your data, then reading them as POSIX
> dates...
2006 Nov 13
1
handling time units--hours, minutes, days--from file times
...lar
intervals. I tried using the zoo package, and had similar problems with the
conversion of time units.
Code and sample data is below--
for your info--after this, I am feeding the times and measurements to nls.
Thanks in advance,
-- Warren
#Here is the failed code:
myfilenames<-row.names(myfileinfo)
fileno<-length(myfilenames)
filetimes<-numeric()
for (i in 2:fileno){rel.read.time<-myfileinfo$mtime[i]-myfileinfo$mtime[1]
rel.read.time<-(as.numeric(rel.read.time))
##this next part is problematic
##i would love to say > time.in.hours<-as.hours
(myfileinfo$mtime[i]-my...