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evalq
2007 May 18
1
subset arg in (modified) evalq
...n model. I would be grateful for a tip how to do this.
Here is an illustration of what I want:
n <- 100
data <- data.frame(x=rnorm(n), y=rnorm(y), z=rnorm(z))
# this works
evalq({ i <- 0<x; summary(y[i] + z[i]) }, data)
# I want to do the above w/o explicit subscripting, e.g.
myevalq(summary(y + z), subset=0<x, data)
Thanks,
Vadim
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