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Hi R-users I can not change the name of one column only of my matrix. my_matrix <- matrix (1:12,ncol=3) colnames(my_matrix)[1] <- 'myname' Error in dimnames(x) <- dn : length of 'dimnames' [2] not equal to array extent thank you for your help Lorenzo [[alternative HTML version deleted]]

I have a matrix of, say, M and N dimensions: my_matrix=matrix(c(1:60),nrow=6,ncol=10) I have two "id" vectors corresponding to the rows and columns, e.g.: id_m=seq(10,60,by=10) id_n=seq(100,1000,by=100) I would like to create a "proper" database (let's say a data.frame for this example -- i'm going to be loading these int...

...lost the source and I hope one of you can point me to the solution. My problem is that I don't know the correct words to query this. When I print to screen a matrix or data.frame the columns are split and printed below the previous ones; even though I have plenty of screen left. E.g., > my_matrix = matrix(runif(30),nrow=3,ncol=10) > my_matrix [,1] [,2] [,3] [,4] [,5] [,6] [,7] [1,] 0.4979305 0.1155717 0.4484069 0.29986049 0.5427566 0.4324351 0.269171456 [2,] 0.8405987 0.3605237 0.6615507 0.75305248 0.8569482 0.3401004 0.192526423 [3,] 0.5608779 0.39539...

...>my.matrix > [,1] [,2] > [1,] 0.708060983 0.3242221 > [2,] 0.356736311 0.1454096 > [3,] 0.402880340 0.4763676 > [4,] 0.795947223 0.4052168 > [5,] 0.001620093 0.2618591 > [6,] 0.192215589 0.6595275 > [7,] 0.539199304 0.5402015 > > > b (m=6,matrix=my_matrix) > [[1]] > matrix.lapply.inf.sup..function.i..c.i..Inf..matrix.i..1...matrix.i.. > 1 1.0000000, Inf, 0.7080610, 0.3242221 > 2 2.0000000, Inf, 0.3567363, 0.1454096 > 3 3.0000000, Inf,...

Hello Everyone, I am using R for creating heatmap from a square matrix. Below is my script to do so my_map <- read.csv("Desktop/input.csv", sep=",") my_matrix <- data.matrix(my_map) my_heatmap <- heatmap(my_matrix, Rowv=NA, Colv=NA, col = cm.colors(256), scale="column", margins=c(5,10)) I get a beautiful plot as output, but I could not save this plot as an image. I would like it to be in either jpg/png/svg/bitmap/ or PDF format. Can so...

...efficient way to 1) read file 2) compute first and second principal components and 3) and plot first vs second PC's ? In the past, I could do this by : b <- read.csv("distance.csv", sep=",", head=F) # distance.csv file is complete data matrix, so this command worked !! my_matrix <- data.matrix(b) pca2 <- princomp(my_matrix) plot(pca2$scores[,1],pca2$scores[,2]) text(pca2$scores[,1],pca2$scores[,2],rownames(nba_matrix), cex=0.5, pos=1) This time, I don't have a complete file. So, I was wondering, how to do this ? Any help is much appreciated TIA M -- View this...

Dear All, While inverting a matrix the following error appears on my console: Error in solve.default(my_matrix) : Lapack routine dgesv: system is exactly singular With this respect, I have been replacing the solve() function with ginv(): the Moore-Penrose generalized inverse of a matrix. These are the questions I would like to ask you: 1. Would you also replace solve() with ginv() in these scenarios...

...ro, below zero is blue of increasing intensity towards -1 and above zero is red of increasing intensity towards red? I tried like this (using the marray and gplots packages from bioconductor): mcol <- maPalette(low="blue", mid="white", high="red",k=100) heatmap.2(my_matrix, col=mcol) But white does not correspond to zero, because the value distribution is not symmetrical, so that zero is not in the middle. Is it somehow possible to create a color palette with white centered at zero? Nick Fankhauser

...w to solve it. I tried to change the amount of ticks using yscale.components, but this doesn't work: yscale.components.myY <- function(...) { Y <- yscale.components.default(...) Y$left$ticks$at <- pretty(1,n=10) Y$left$labels$at <- pretty(1,n=10) return(Y) } print(levelplot(my_matrix),cuts=100,yscale.components=yscale.components.myY) My full code can be found on pastebin: http://pastebin.com/m16b267f9 thanks in advance for any help on this, Bram Kuijper

Hi all, I have a bunch of int vectors. Each vector holds a bunch of ints that correspond to row numbers of an existing matrix. I use the int vectors to pull out rows of data from a matrix, i.e. data <- my_matrix[int_vector,] I would like to store these int vectors in some sort of data structure that will preserve them as-is and allow iteration. I guess what I'm looking for would be something analogous to the java Vector class, as in this java-like pseudocode : Vector V = new Vector; V.add(a,b,c) /...

...something like this: carmake<-c("Toyota","Ford","Chevy") x<-matrix(1:12,nrow=4) colnames(x)<-c("Car1","Car2","Car3") rownames(x)<-c("Horsepower","TopSpeed","Weight","Cost") res<-apply(my_matrix,2,my_func,carmake) The obvious problem with this is that I cannot know which column 'my_func' is working on, in order to know which column to get the car make from. I then thought I could try and match on column name, but when the column is passed into 'my_func' it loses the column...

Hi there, Could anyone please help me to understand what should be done in order not to get this error message: Error: evaluation nested too deeply: infinite recursion / options(expressions=)? Here is my code: determinant<- function(x){det(matrix(c(1.0,0.2,0.5,0.8,0.2,1.0,0.5,0.6,0.5,0.5,0.5,1.0,x,0.8,0.6,x,1.0),ncol=4,byrow=T))} matrix<-

...t; Content-Type: text/plain; charset=utf-8 Hi Ana, There are two problems: First of all, if you want your matrix to have 4 columns it's number of elem[[elided Yahoo spam]] Secondly, and this is what causes your error message, you should not call your second function matrix. Call it matrix1, my_matrix, whatever. Otherwise R thinks that you are calling your matrix function within itself. > Subject: [R] Calculating interval for conditional/unconditional correlation matrix > To: "R" <r-help@r-project.org> > Received: Sunday, 21 September, 2008, 8:05 PM > Hi there, &...