search for: mutipli

Displaying 4 results from an estimated 4 matches for "mutipli".

Did you mean: mutiple
2005 Feb 28
1
Using mutiply imputed data in NLME
Dear All, I am doing a growth modeling using NLME. I have three levels in my data: observation, individual, household. About half of my total sample have missing values in my household-level covariates. Under this situation, the best way to go is probably to multiply impute the data (for, say, 5 times), estimate the same model separately on each model using LME function, and merge the results. My
2011 Feb 21
1
Mutiplying a data frame to a list
Hi R community, I have a question I'm sure is very simple for most of you. I have a list, with each element being a matrix and the names of the elements are numbers (like 1,3,...). I can extract the matrices and the names individually. Now, I want to multiply each of the names to the individual list matrices (after converting to numbers of course). I could use a for loop, but the very
2006 Jun 27
1
related to my previous sapply question]
in my previous post in which i asked about creating sequences from two vectors of numbers, all suggestions worked. tradevectors<-mapply(seq,from=tempa,to=tempb) or tradevectors<-sapply(1:length(tempa),function(x) seq(tempa[x],tempb[x]) >both return a list with 3 components. the problem is that i want to take these 3 sequences and use them as the indices of two other vectors, X and
2011 Apr 08
0
Fwd: The results of your email commands
...that some of the content was "unprocessed". Hence, I am reposting the question just to be sure (sorry for the multiple emails if both reached you). My question is reagarding the way we use constraints in programs like maxBFGS, etc. We need to put two matrices into a list, containing the mutipliers on the LHS of the constraint equations and the constants on the RHS. I want to constrain the last parameter of my routine to a negative value. Hence, I specify: lhs=matrix(0,nrow=noOfParameters,ncol=noOfParameters) lhs[noOfParameters,noOfParameters]=-1 rhs=matrix(0,nrow=(noOfParameters)) Then...