search for: mtrix

Hi all, I have 2 columns in a mtrix, one of which is a column of probabilities and the other is simply a vector of integers. I want to sum all the probabilities with the same integer value and put it in a new column. For example, If my matrix is: 0.98 2 0.2 1 0.01 2 0.5 1 0.6 6 Then I should get: 0.98 2 0.99 0...

Full_Name: Anne CORI Version: 2.6.1 OS: windows Submission from: (NULL) (134.157.220.19) let A be a mtrix with n lines and p columns, p>36 ; matplot(A) will only draw the plot of the first 36 columns of A. This is due to a bug in the definition of pch in the function : pch <- c(paste(c(1:9, 0)), letters)[1:k] should be replaced by pch <- c(paste(c(1:9, 0)), letters) I hope this is clea...

dear R users, I have fit the lm() on a mtrix of responses. i.e M1 = lm(cbind(R1,R2)~ X+Y+0). When i use summary(M1), it shows details for R1 and R2 separately. Now i want to use stepAIC on these models. But when i use stepAIC(M1) an error message comes saying that dropterm.mlm is not implemented. What is the way out to use stepAIC in such c...

Hello everyone, I have a 2 x 5 matrix: say 0.2 0.3 1 -1 3 0.2. 0.4 5 0.5 -1 I want to replace all the values greater than or equal to 1 with 1 and those less than or equal to 0 with 0. So I should end up with a mtrix looking like: 0.2 0.3 1 0 1 0.2. 0.4 1 0.5 0 Any ideas how to do this? -- Thanks, Jim. [[alternative HTML version deleted]]

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Dear list, Im trying to do the following operation but im not able to do it This is my table: 1 2 3 1 0 7 4 2 0 2 0 3 0 1 3 4 0 3 4 what i would like to do is divide each row values with the corresponding column' sum,namely: 1 2 3 1 0 0.54 0.36 2 0 0.15 0 3 0 0.08

Is there a way of removing all rows with missing values from a data frame? I usually use subset(x, var1!="NA") and repeat for each variable. It would be nice to be able to do it in one fell swoop. Also, surprisingly, it doesn't always work. Sometimes I'm left with an empty set even though not all rows have missing values for the variable. Cheers, mikkel Mikkel Grum,