Displaying 9 results from an estimated 9 matches for "mt2".
Did you mean:
m32
2001 Jun 05
2
a bug? (PR#968)
...0 0
502 M07 MT1 MT 180 10 0
503 M07 MT1 MT 180 10 0
504 M07 MT1 MT 180 10 0
505 M07 MT1 MT 180 10 0
506 M07 MT1 MT 180 10 0
507 M07 MT1 MT 180 10 0
508 M07 MT1 MT 180 10 0
509 M07 MT1 MT 180 10 0
510 M07 MT1 MT 180 10 0
511 M07 MT1 MT 180 10 0
512 M07 MT1 MT 180 10 0
513 M07 MT1 MT 180 10 0
514 M08 MT2 MT 180 10 1
515 M08 MT2 MT 180 10 1
516 M08 MT2 MT 180 10 1
517 M08 MT2 MT 180 10 1
518 M08 MT2 MT 180 10 1
519 M08 MT2 MT 180 10 1
520 M08 MT2 MT 180 10 1
521 M08 MT2 MT 180 10 1
522 M08 MT2 MT 180 10 1
523 M08 MT2 MT 180 10 1
524 M08 MT2 MT 180 10 1
525 M08 MT2 MT 180 10 1
526 M08 MT2 MT 180 10 0...
2008 Jan 06
3
need help
Hi,
I'm Roslina, PhD student of University of South Australia, Australia
from school Maths and Stats. I use S-Plus before and now has started
using R-package. I used
to analyse rainfall data using julian date. Is there any similar
function that you can suggest to me to be used in R-package? Thank you
so much for your attention and help
[[alternative HTML version deleted]]
2013 Jan 20
2
Lattice levelplot- remove unused levels per panel
Hi,
I am using levelplot, and would like remove from each panel (condition) its
unused x levels.
e.g.
Remove from panel vs=1 the cyl level=8.
data(mtcars)
levelplot(mpg~factor(cyl)*factor(gear)|factor(vs))
Thanks for your help,
Ronny
--
View this message in context: http://r.789695.n4.nabble.com/Lattice-levelplot-remove-unused-levels-per-panel-tp4656087.html
Sent from the R help mailing
2012 Jun 12
4
How to index a matrix with different row-number for each column?
here's my question: suppose I have a matrix:
mt<-matrix(1:12,ncol=6)
now I have a vector
vt<-c(1,2,2,2,1,2)
which means I want to get:
the 1st row for column1;
the 2nd row for column2;
the 2nd row for column3;
the 2nd row for column4;
...
that what I want is this vector:
1,4,6,8,9,12
Does anyone know how to do this fast?
I know I can use for-loop to travel all columns,but
2011 Sep 27
3
remove NaN from element in a vector in a list
Hello,
What is the best way to turn a matrix into a list removing NaN's? I'm new to
R...
Start:
> mt = matrix(c(1,4,NaN,5,3,6),2,3)
> mt
[,1] [,2] [,3]
[1,] 1 NaN 3
[2,] 4 5 6
Desired result:
> lst
[[1]]
[1] 1 3
[[2]]
[1] 4 5 6
Thanks!
Ben
[[alternative HTML version deleted]]
2012 Jun 12
1
Analyzing large files faster
....P.Val" "logFC" "Gene.symbol"
"1419156_at" "5.32e-12" "2.6462565" "Sox4"
"1433575_at" "5.32e-12" "3.9417089" "Sox4"
"1428942_at" "2.64e-11" "3.9163618" "Mt2"
"1454699_at" "2.69e-10" "1.8654677" "LOC100047324///Sesn1"
"1416926_at" "3.19e-10" "2.172342" "Trp53inp1"
"1422557_s_at" "1.58e-09" "2.9569254" "Mt1"
etc.
using the followi...
2007 Jun 08
2
wrapping lattice xyplot
This is an expanded version of the question I tried to ask last night
- I thought I had it this morning, but it's still not working and I
just do not understand what is going wrong.
What I am trying to do is write a wrapper for lattice xyplot() that
passes a whole bunch of its secondary arguments, so that I can produce
similarly formatted graphs for several different data sets. This is
what
2018 Apr 27
5
predict.glm returns different results for the same model
Hi all,
Very surprising (to me!) and mystifying result from predict.glm(): the
predictions vary depending on whether or not I use ns() or
splines::ns(). Reprex follows:
library(splines)
set.seed(12345)
dat <- data.frame(claim = rbinom(1000, 1, 0.5))
mns <- c(3.4, 3.6)
sds <- c(0.24, 0.35)
dat$wind <- exp(rnorm(nrow(dat), mean = mns[dat$claim + 1], sd =
sds[dat$claim + 1]))
dat <-
2004 Apr 16
3
R-1.9.0: make error on slackware-current!
My box: Slackware-current, Xfree 4.4.
ERROR as follows:
gcc -I. -I../../../src/include -I../../../src/include -I/usr/X11R6/include
-I/usr/local/include -DHAVE_CONFIG_H -D__NO_MATH_INLINES -mieee-fp -fPIC
-g -O2 -c dataentry.c -o dataentry.lo
In file included from dataentry.c:31:
/usr/X11R6/include/X11/Xlib.h:1390: error: parse error before "_Xconst"