Displaying 20 results from an estimated 40 matches for "moshersteven".
2011 Sep 12
5
Hourly data with zoo
I have date data as a numeric and hourly data in 0 to 2300 hours in a dataframe.
d <- rep(20110101,24)
h <- seq(from = 0, to = 2300, by = 100)
df <- data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1))
S <- chron(dates. = as.character(df$LST_DATE), times. =
paste(as.character(df$LST_TIME/100), ":0:0", sep = ""),
format =
2010 Apr 25
3
Noobie question on aggregate tapply and by
I have a 43MB dataframe ( 5 variables) and I'm trying to summarize subsets
of the data.
I've RTFM ( not very clear) and looked at a variety of samples but cant seem
to figure out
how to make these functions work.
A sample of what I want to do would be this:
ids<-seq(1,50)
years<-c(rep(5,10),rep(6,10),rep(7,10),rep(8,20))
2011 May 27
2
help with barplot
Hi,
I'm really struggling with barplot
I have a data.frame with 3 columns. The first column represents an
"incident" type
The second column represents a "month"
The third column represents a "time"
Code for a sample data.frame
incidents <- rep(c('a','b','d','e'), each =25)
months <- rep(c(1,2), each =10)
times
2010 Aug 11
2
Sweeping a zoo series
Given a long zoo matrix, the goal is to "sweep" out a statistic from the
entire length of the
sequences.
longzoomatrix<-zoo(matrix(rnorm(720),ncol=6),as.yearmon(outer(1900,seq(0,length=120)/12,"+")))
cnames<-c(12345,23456,34567,45678,56789,67890)
colnames(longzoomatrix)<-cnames
longzoomatrix[1:24,]
12345 23456 34567 45678
2010 Jun 05
5
Matrix to Vector
Given a matrix of m*n, I want to reorder it as a vector, using a row major
transpose.
so:
> m<-matrix(seq(1,48),nrow=6,byrow=T)
> m
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
[1,] 1 2 3 4 5 6 7 8
[2,] 9 10 11 12 13 14 15 16
[3,] 17 18 19 20 21 22 23 24
[4,] 25 26 27 28 29 30 31 32
[5,] 33 34 35 36 37
2010 May 04
1
error in La.svd Lapack routine 'dgesdd'
Error in La.svd(x, nu, nv) : error code 1 from Lapack routine ‘dgesdd’
what resources are there to track down errors like this
[[alternative HTML version deleted]]
2010 Jun 14
1
recursively Merging a list a zoo objects
The zoo package as a merge function which merges a set of zoo objects
result<-merge(zoo1,zoo2,...)
Assume your zoo objects are already collected in a list
# make a phony list to illustrate the situation. ( hat tip to david W for
constructing a list in a loop)
ddat <- as.list(rep("", 20))
ytd<-seq(3,14)
for(i in 1:20) {
+ ddat[[i]] <- zoo(data,ytd )
+ }
ddat
[[1]]
1 2
2010 Aug 09
1
nested 'by'
Assuming a data frame or matrix with two columns representing variable that
you want to aggregate over.
you want to calculate column means, by year, for each Id
example<-data.frame(id=c(rep(12345,5),rep(54321,6),rep(45678,7)),Year=rep(seq(1900,1902,by=1),6),
x=seq(1,18,by=1),y=seq(18,1,by=-1))
example
id Year x y
1 12345 1900 1 18
2 12345 1901 2 17
3 12345 1902 3 16
4 12345
2010 Sep 21
1
diagnosing download.file() problems
I'm accessing around 95 tar files on an FTP server ranging in size between
10 and 40MB a piece.
while certainly can click on them and download them outside of R, I'd like
to have my script do it.
Retrieving the ftp directory with RCurl works fine (about 90% of the time)
but downloading the files by looping through all the files is a random
process.
I may get 1-8 files download and then
2010 Aug 15
1
Trouble loading "saved" Rdata
In the particular application I have I save "test.Rdata" to a sub directory
dir<-"Example"
dir.create(dir)
test<-data.frame(a=c(1,2,3),b=c(3,4,5)
full<-file.path(dir,"test.Rdata,fsep=.Platform$file.sep)
save(test,file=full)
load(full)
returns NULL
it works fine when the object is saved to the working directory, but fails
when saved to a sub directory.
The Rdata
2010 Aug 20
1
differecing a zoo series
A quick question
x <- as.yearmon(2000 + seq(0, 23)/12)
x
[1] "Jan 2000" "Feb 2000" "Mar 2000" "Apr 2000" "May 2000" "Jun 2000" "Jul
2000" "Aug 2000" "Sep 2000" "Oct 2000" "Nov 2000" "Dec 2000" "Jan 2001"
[14] "Feb 2001" "Mar 2001" "Apr
2010 Dec 21
1
lm() on a matrix of zoo series
I have a matrix of zoo series. each series is in a column.
x <- as.yearmon(2000 + seq(0, 23)/12)
# 24 months of data, lets make 20 sets of random data
testData <- matrix(rnorm(480),ncol=20)
# make a zoo object and columns will hold the 20 series
TestZoo <- zoo(testData,order.by=x)
# now run lm for just one series.
m <- lm(TestZoo[,1]~time(TestZoo))$coeff[2]
m
time(TestZoo)
2011 Nov 01
1
weird error
I was just rebuilding a package that has built before and I hit this error
Error in loadNamespace(package, c(which.lib.loc, lib.loc), keep.source =
keep.source) :
cyclic name space dependency detected when loading 'GhcnDaily', already
loading 'GhcnDaily'
The package built just fine last revision, and the only changes I made were
to Rd files
How do I track this puppy down
2010 May 05
1
extracting a matched string using regexpr
Given a text like
I want to be able to extract a matched regular expression from a piece of
text.
this apparently works, but is pretty ugly
# some html
test<-"</tr><tr><th>88958</th><th>Abcdsef</th><th>67.8S</th><th>68.9\nW</th><th>26m</th>"
# a pattern to extract 5 digits
> pattern<-"[0-9]{5}"
#
2010 Oct 09
1
Loss of precision in read.csv.
Given a csv file from this location
Airports<-"http://www.ourairports.com/data/airports.csv"
download.file(Airports,basename(Airports))
airports <-read.csv("airports.csv",encoding="UTF-8")
> airports[1,]
id ident type name latitude_deg longitude_deg
elevation_ft continent iso_country iso_region municipality scheduled_service
1 6523
2011 Jul 27
2
Elegant way to subtract matrix from array
there are really two related problems here
I have a 2D matrix
A <- matrix(1:100,nrow=20,ncol =5)
S <- matrix(1:10,nrow=2,ncol =5)
#I want to subtract S from A. so that S would be subtracted from the
first 2 rows of
#A, then the next two rows and so on.
#I have a the same problem with a 3D array
# where I want to subtract Q for every layer (1-10) in Z
# I thought I solved this one
2011 Mar 18
2
Understanding tryCatch
I've read the help and the archives on tryCatch but I'm still stuggling
trying to understand how it
works exactly and how I can use it to get the result I need.
I have a data.frame of urls which point to 11 .zip files. Basically I use
RCurl to get the list of
files from a ftp and then reduce that directory dump to the 11 zip files I
want to download.
Its easy enough to do that in a loop
2010 Jul 15
3
Summing over intervals
Given a matrix of MxN
want to take the means of rows in the following fashion
m<-matrix(seq(1,80),ncol=20, nrow=4)
result<-matrix(NA,nrow=4,ncol=20/5)
result[,1]<-apply(m[,1:5],1,mean)
result[,2]<-apply(m[,6:10],1,mean)
result[,3]<-apply(m[,11:15],1,mean)
result[,4]<-apply(m[,16:20],1,mean)
result
[,1] [,2] [,3] [,4]
[1,] 9 29 49 69
[2,] 10 30 50 70
2010 Aug 07
1
Data frame reordering to time series
Given a data frame, or it could be a matrix if I choose to.
The data consists of an ID, a year, and data for all 12 months.
Missing values are a factor AND missing years.
Id<-c(rep(67543,4),rep(12345,3),rep(89765,5))
Years<-c(seq(1989,1992,by =1),1991,1993,1994,seq(1991,1995,by=1))
Values2<-c(12,NA,34,21,NA,65,23,NA,13,NA,13,14)
Values<-c(12,14,34,21,54,65,23,12,13,13,13,14)
2010 Sep 15
2
Get File Names in Folder, Read Files, Update, and Write
Dear All,
Could you please recommend how I can do this?
I have several text files in one folder. Let's name them A0801.RSK,
A0802.RSK, ....
I would like R to
1) Know all file names in this folder
2) Update value in one column of these files
3) Write results in another text file with _xval in the file names
Below is R code for read, update, and write one file