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On Sat, May 1, 2010 at 11:02 AM, Mohan L <l.mohanphy@gmail.com> wrote: > Hi All, > > I am new to R and the mailing list. > > I have a data file (.xls) format with little bit large (16 column,35000 > rows ) data file. I am trying to read this file for calculation. I have > converted the file into .csv format and read like that : > > > bmtrend <-

Dear All, > avglog 01/11/09 02/11/09 03/11/09 04/11/09 9.750000 4.500000 4.500000 8.666667 > avglog1 <- data.frame(avglog) > avglog1 avglog 01/11/09 9.750000 02/11/09 4.500000 03/11/09 4.500000 04/11/09 8.666667 The first column isnt a column, It's the row names. I makeing a column from the row names by using the following > value1$Day <- rownames(value1) >

Dear All, I have data some thing like this: > sample State Jan Feb Mar A 1 1 1 B 1298 1293 1294 C 0 0 0 D 5 5 5 E 18 18 18 I need to multiply "Jan" column *1000 and divided by the same number, like this : > data[,-(1:2)] * ((data[,2] *1000)/data[ ,2]) I doing some thing

Hi All, I am new to R and the mailing list. I have a data file (.xls) format with little bit large (16 column,35000 rows ) data file. I am trying to read this file for calculation. I have converted the file into .csv format and read like that : > bmtrend <- read.csv(file="simple.csv",head=TRUE,sep=",") > bmtrend will display something in the middle of display [

Dear All, I have data some thing like this: State Jan Feb Mar Apr May Jun AAA 1 1 0 2 2 0 BBB 1298 1195 1212 1244 1158 845 CCC 0 0 0 1 2 1 DDD 5 11 17 15 10 9 EEE 18 28 27 23 23 16 FFF 68 152 184 135 111 86 I want to sum all the column(Jan, Feb, Mar ...) and have to merge the total at last row. like this: StateJanFebMarAprMayJunAAA110220BBB12981195121212441158845CCC 000121DDD51117

Dear All, I have data some thisng like this : > data <- read.csv(file='ipsample.csv',sep=',' , header=TRUE) > data State Jan Feb Mar Apr May Jun 1 AAA 1 1 0 2 2 0 2 BBB 1298 1195 1212 1244 1158 845 3 CCC 0 0 0 1 2 1 4 DDD 5 11 17 15 10 9 5 EEE 18 28 27 23 23 16 6 FFF 68 152 184 135 111

Hi all, I have data like this: >sample <- read.csv(file="sample.csv",sep=",",header=TRUE) > sample stdate Domain sex age Login 1 01/11/09 xxx FeMale 25 2 2 01/11/09 xxx FeMale 35 4 3 01/11/09 xxx Male 18 30 4 01/11/09 xxx Male 31 3 5 02/11/09 xxx Male 32 11 6 02/11/09 xxx Male 31 1 7 02/11/09

Hi All, I have the data like this : >sample <- read.csv(file="sample.csv",sep=",",header=TRUE) > sample stdate Domain sex age Login 1 01/11/09 xxx FeMale 25 2 2 01/11/09 xxx FeMale 35 4 3 01/11/09 xxx Male 18 30 4 01/11/09 xxx Male 31 3 5 02/11/09 xxx Male 32 11 6 02/11/09 xxx Male 31 1 7 02/11/09

Unsubscribe -----Original Message----- From: r-help-request at r-project.org Date: Wed, 05 May 2010 12:00:09 To: <r-help at r-project.org> Subject: R-help Digest, Vol 87, Issue 5 Send R-help mailing list submissions to r-help at r-project.org To subscribe or unsubscribe via the World Wide Web, visit https://stat.ethz.ch/mailman/listinfo/r-help or, via email, send a message with subject

Dear All, I am executing my R script from PHP using the shell_exec. $return = shell_exec("/usr/bin/R --slave --args ".$Domain.",".$Gender." < /var/www/html/trends/newTrend.R"); In newTrend.R, I am plotting graph and save in pdf file using the below code. It will create a pdf file with two line. pdf(file="/var/www/html/trends/bmtrend.pdf", height=7.5,

Dear All, I have a data frame with State and 12 Months as column. I want to convert all the 12 month column from factor to numeric. any help will be greatly appreciated. > str(data) 'data.frame': 33 obs. of 9 variables: $ State : Factor w/ 33 levels "Andaman and Nicobar Islands",..: 1 2 3 4 5 6 7 8 9 10 ... $ April : Factor w/ 21 levels

Dear All, I have a data frame "data" with Jan , Feb as column. I using like this data$Jan to take Jan column. I have the Jan in another variable var1 <- "Jan" data$var1 I need to replace the variable value there . Any help will be greatly appreciated. Thanks & Rg Mohan L [[alternative HTML version deleted]]

Dear All, I have an array some thing like this: > avglog January February March April May June July August September 60102 83397 56774 48785 49010 40572 38175 47037 51402 The class of "avglog" array. > class(avglog) [1] "array" > str(avglog) num [1:9(1d)] 60102 83397 56774 48785 49010 ... - attr(*,

Hi all, I have data size of : > dim(sample) [1] 35943 17 The first column is "stdate" - is date ( 01/11/2009 00:00:00,02/11/2009 00:00:00,02/11/2009 00:00:00 etc... ) Login is 13th column - is numbers (12,0,1 erc...) The below operation return the following error. > sample1 <- read.csv(file="sample1.csv",sep=",",header=TRUE) > avglog <-

Dear All, I have the data some thing like this, I am showing here three days data only: > dummy.data <- read.table(file='dummy.txt',sep='', header=TRUE) > dummy.data StDate Domaindesc Logins 1 05/01/10 xxx 10 2 05/01/10 xxx 45 3 05/01/10 xxx 2 4 05/01/10 yyy 45 5 05/01/10 yyy 20 6 05/01/10 yyy

I have the raw data with 9 column and 197977 row: > dummy State Months Bedroom 1 xxx Jan 1 2 xxx Jan 2 3 xxx Jan 1 4 yyy Jan 1 5 yyy Jan 2 6 yyy Jan 1 7 zzz Jan 3 8 zzz Jan 1 9 zzz Jan 2 10 xxx Feb 3 11 xxx Feb 4 12 xxx Feb 2 13 yyy Feb 1 14

Dear All, I have a data frame "data" and the below is the str of "data" : $ Feb : int 1 1195 0 11 28 152 24 2 1 1470 ... $ Mar : int 0 1212 0 17 27 184 15 1 1 1311 ... $ Apr : int 2 1244 1 15 23 135 11 0 1 991 ... $ May : int 2 1158 2 10 23 111 16 1 1 1237 ... $ Jun : int 0 845 1 9 16 86 16 2 1 1129 ... $ Jul : int 0 832 0 7 16 68 9 1 0 994 ... $ Aug

Hello. I would like to ask about having mysql data hosted on glusterfs. Please see my issue below. I have posted DEBUG log information on pastebin. I am using GlusterFS version: glusterfs 1.4.0rc7 FUSE Version :fuse-2.7.3glfs10 my ISSUE is: When hosting mysql data on glusterfs I have an issue: The first time I start the glusterfsd server using [root at mohan ~]#