search for: modetable

Hi list, I am in need of a "special" asterisk conference room with the following constraints: - there is one admin / moderator and several "normal" callers. - the callers must not hear any other caller, only the moderator - the moderator must be able to mute and unmute any caller at any time - the moderator must be able to talk to all callers or to a specific caller. - the

...the modes of a value set # Based on Ross NELSONs code from 2004-11-16 (on R-help mailling list) # create a table with the values sorted by frequency sortvar <- sort(table(x)) # get the max frequency maxfreq <- max(sortvar) # find values with high frequency modeTable <- which(sortvar == maxfreq) # get the name (value) of the most frequent value themoderesult <- names(modeTable) # Report return(themoderesult) # data(CO2) # modus(CO2$uptake) # rm(CO2) } -- Lep pozdrav / With regards / Con respeto, Gregor GORJANC...

...the modes of a value set # Based on Ross NELSONs code from 2004-11-16 (on R-help mailling list) # create a table with the values sorted by frequency sortvar <- sort(table(x)) # get the max frequency maxfreq <- max(sortvar) # find values with high frequency modeTable <- which(sortvar == maxfreq) # get the name (value) of the most frequent value themoderesult <- names(modeTable) # Report return(themoderesult) # data(CO2) # modus(CO2$uptake) # rm(CO2) } -- Lep pozdrav / With regards / Con respeto, Gregor GORJANC...

built-in; This doesn=92t matter because the moderator would have to use meetmeadmin or the confbridge equivalent to control the other functions. The moderator would either need two phones or a phone and a web = interface. Let=92s say Yves=92 =93special conference=94 is 5555. The moderator = would start using this command Exten =3D> s,1,meetme(5555) The participants would do Exten =3D>

Hello my problem is the following: I have a matrix A and a vector B which contains as many rows as A. I need to build a matrix C which contains B[i]-times the row A[i,] and this for each line of A. if for example A is [1] [2] [1] 8 9.4 [2] 4.2 1.1 and B is (3,1). Then C will be: [1] [2] [1] 8 9.4 [2] 8 9.4 [3] 8 9.4 [4] 4.2 1.1 I have some