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...toped working. The log file shows nothing new. No error ... Only the clients can not connect to the server. After a restart of smbd it seems to work for a while. Any idea ? Any help is welcome !! ---------The last logline before was 10:39; at10:42 no connection was possible----- Jan 7 10:42:30 modena smbd[9266]: nss_ldap: reconnected to LDAP server after 1 attempt(s) Jan 7 10:42:40 modena smbd[9266]: [2008/01/07 10:42:40, 0] smbd/service.c:make_connection(1191) Jan 7 10:42:40 modena smbd[9266]: namibia (141.5.19.206) couldn't find service c-sid Jan 7 10:42:42 modena smbd[9784]: nss_...

...result contour(xgr,xgr,Bmat) persp(xgr,xgr,Bmat,theta=15) any of you have a better idea (ie more efficient)? Thanks in advance, Patrizio Frederic +------------------------------------------------- | Patrizio Frederic | Research associate in Statistics, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

...you knows about some R implementations (packages) for computing BSA. Many thanks in advance, Patrizio as usual I apologize for my fragmented English -- +------------------------------------------------- | Patrizio Frederic, PhD | Assistant Professor, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

...ting out the multiple figure layout with, e.g., par(mfrow=c(2, 2,)) does not work. Does anybody know a workaround for this? Many thanks in advance for any advice best giuseppe -- Giuseppe Pagnoni, PhD Dip. Scienze Biomediche, Metaboliche e Neuroscienze Sezione Fisiologia e Neuroscienze Univ. di Modena e Reggio Emilia Via Campi 287 I-41125 Modena, Italy Tel: +39-059-205-5742 Fax: +39-059-205-5363 [[alternative HTML version deleted]]

Hi all, I am running a bivariate regression with the following: p1=c(184,155,676,67,922,22,76,24,39) p2=c(1845,1483,2287,367,1693,488,435,1782,745) I1=c(1530,1505,2505,204,2285,269,1271,298,2023) I2=c(8238,6247,6150,2748,4361,5549,2657,3533,5415) R1=I1-p1 R2=I2-p2 x1=cbind(p1,R1) y1=cbind(p2,R2) fit1=lm(y1~-1+x1) summary(fit1) Response 2: Coefficients: Estimate Std. Error t value

...04 day 22 svn rev 45424 language R version.string R version 2.7.0 (2008-04-22) thank you in advance, Patrizio Frederic ------------------------------------------------- | Patrizio Frederic | Research associate in Statistics, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

...he machines are running the latest version of R (3.0.1) and nlme package (3.1-109) as of today (updated from the CRAN master site). Many thanks in advance for any suggestions, best -- Giuseppe Pagnoni Dip. Scienze Biomediche, Metaboliche e Neuroscienze Sezione Fisiologia e Neuroscienze Univ. di Modena e Reggio Emilia Via Campi 287 I-41125 Modena, Italy Tel: +39-059-205-5742 Fax: +39-059-205-5363 [[alternative HTML version deleted]]

...dvance to anybody who'd be so kind to offer their advice or tip on this. I have scoured the web and some textbooks for a few days now, but to little avail. very best giuseppe -- Giuseppe Pagnoni Dip. Scienze Biomediche, Metaboliche e Neuroscienze Sezione Fisiologia e Neuroscienze Univ. di Modena e Reggio Emilia Via Campi 287 I-41125 Modena, Italy Tel: +39-059-205-5742 Fax: +39-059-205-5363

...I loose factors labels > sapply(data,choose.last) V1 V2 V3 1 1 3 0.4 2 2 1 NA 3 3 1 1.1 any hint? Thanks in advance, Patrizio +------------------------------------------------- | Patrizio Frederic, PhD | Research associate in Statistics, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

...sion (2,3,12) which contains each matrix @cval produced by ca.jo for the 12 subjects that i tested. Can anyone help me with that? I hope my explanation of the problem is clear. Thanks in advance for any help. -- Francesca ---------------------------------- Francesca Pancotto, PhD Università di Modena e Reggio Emilia Viale A. Allegri, 9 40121 Reggio Emilia Office: +39 0522 523264 Web: http://www2.dse.unibo.it/francesca.pancotto/ ---------------------------------- [[alternative HTML version deleted]]

...t;) : ReadItem: unknown type 136, perhaps written by later version of R I've no idea of what type 136 is. Any hints? Thanks in advance, Patrizio -- +------------------------------------------------- | Patrizio Frederic, PhD | Assistant Professor, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

Dear all, I'm stuck in a seemingly trivial task that I need to perform for many datasets. Basically, I want to replace NA with 0 in a specified range of columns in a dataframe. I know the first and last column to be recoded only by its name. I can select the columns starting like this a[match('first',names(a)): match('last',names(a))] The question is how can replace all NA

...ith tsboot? Or how might I write my "statistic" in tsboot? I am using: R version 2.11.1 (2010-05-31) on a Debian testing x86_64 Thanks, regards, Alessandro -- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Alessandro Bigi Dipartimento di Ingegneria Meccanica e Civile University of Modena and Reggio Emilia via Vignolese 905/b, I-41125 Modena phone: +39-059-2056328 fax: +39-059-2056126 skype: ale.bigi email: alessandro.bigi at unimore.it ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Hi, I would like to generate two correlated variables. I found that funktion for doing that: a <- rmvnorm(n=10000,mean=c(20,20),sigma=matrix(c(5,0.8*sqrt(50), 0.8*sqrt(50),10),2,2)) (using library(mvtnorm)) Now I also want to generate two correlated variables where the error variance vary over the variable-correlation. And I want to plot this for showing heteroscedasticity. Like shown

Hi, In order to use the mle2-function, one has to define the likelihood function itself. As we know, the likelihood function is a sum of the logarithm of probability density functions (pdf). I have implemented myself the pdfs that I am using. My problem is, that the pdfs values are negative and I cann't take the logarithm of them in the log-likelihood function. So how can one take the

Hi, At each iteration in my program,I need to generate tree vectors,X1,X2,X3, from exponential distribution with parameters a1,a2,a3. Can you help me please how can I do it such that it take a little time? thank you khazaei

Dear group, Here are my objects in my environment: > ls() [1] "Pos100415" "Pos100416" "posA" "pose15" "pose16" "pose16t" "position" "trade" "x" I need to pass the object "Pos100415" to a function. This element is a data.frame, obtained through a function: Pos(x)<-myfun(x)

Hi R-users, I have this code to uniformise the data using gamma: > length(dp1) [1] 696 > dim(dp1) [1] 58 12 > dim(ahall) [1]  1 12 > dim(bhall) [1]  1 12 > trans_dt <- function(dt,a,b) + { n1 <- ncol(dt) +   n2 <- length(dt) +   trans  <- vector(mode='numeric', length=n2) +   dim(trans) <- dim(dt) +   for (i in 1:n1) +   {  dt[,i] <- as.vector(dt[,i])

...ly the geographical location of the sampling points ? Thanks a lot for the attention !!! Stef ------------------------------------------------------------------------ Stefano Marchesi Environmental Epidemiologic Unit Environmental Protection Agency - ARPA Emilia Romagna Via Fontanelli 23 - 41100 Modena (Italy) tel: +39 059 433635 (int. 5035) fax: +39 059 241312 sito web: www.arpa.emr.it/epam

Dear R Users, I am executing the following command to produce a line graph: matplot(aggregate_1986[,1], aggregate_1986[,2:3], type="l", col=2:3) On the x-axis I have values of Latitude (in column 1) ranging from -60 to +80 (left to right on the x-axis). However, I wish to have these values shown in reverse on the x-axis, going from +80 to -60 (ie. North to South in terms of Latitude).