search for: mmn2

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2010 Jan 18
2
Predict polynomial problem
..., and also on R 2.8.1 I had lying around on a Windows box: d = data.frame(x=1:10,y=runif(10)) lmn <- function(d,n){ models=list() for(i in n){ models[[i]]=lm(y~poly(x,i),data=d) } return(models) } mmn = lmn(d,3) predict(mmn[[3]]) predict(mmn[[3]],newdata=data.frame(x=c(9,10,11))) mmn2 = lmn(d,3:5) predict(mmn2[[3]]) predict(mmn2[[3]],newdata=data.frame(x=c(9,10,11))) Barry