Displaying 9 results from an estimated 9 matches for "mlamia".
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mlaia
2010 May 11
3
Improving loop performance
R-users,
I have the following piece of code which I am trying to run on a dataframe (aga2) with about a half million records. While the code works, it is extremely slow. I've read some of the help archives indicating that I should allocate space to the p1 and ags1 vectors, which I have done, but this doesn't seem to improve speed much. Would anyone be able to provide me with advice on
2000 Apr 04
2
Loading Problem
I'm using R0.90.1 on Win98. I'm trying to load an image I saved yesterday
but I keep getting the following error:
Error in load("C:/temp/245amData.R.RDa") : restore file corrupted -- no data
loaded
The image is 4,890KB.
The image Can anyone tell me how to solve this problem? I'm sure I saved
the image correctly.
Thanks.
Mark
Mark J. Lamias
Department of Statistics
2010 May 12
2
R version of SAS/IntrNet
Does an R package exist that is similar to SAS/Intrnet (http://support.sas.com/documentation/onlinedoc/intrnet/index.html) that will allow users to take parameters passed to it by a web request, produce results and return them to the web-browser in HTML format? I tried looking through the package descriptions, but didnt' see anything like this. Any direction or suggestions you could provide
2012 Oct 12
3
Autofilling a large matrix in R
I wish to create a matrix of all possible percentages with two decimal place
percision. I then want each row to sum to 100%. I started with the code
below with the intent to then subset the data based on the row sum. This
works great for 2 or 3 columns, but if I try 4 or more columns the number of
rows become to large. I would like to find a way to break it down into some
kind of for loop, so
2012 Nov 29
5
bootstrapped cox regression (rms package)
Hi,
I am trying to convert a colleague from using SPSS to R, but am having
trouble generating a result that is similar enough to a bootstrapped cox
regression analysis that was run in SPSS. I tried unsuccessfully with
bootcens, but have had some success with the bootcov function in the rms
package, which at least generates confidence intervals similar to what is
observed in SPSS. However, the
1999 Dec 07
1
Bug list summary (automatic post)
...From: albrecht.gebhardt@uni-klu.ac.at
Date: Tue, 30 Nov 1999 14:28:10 +0100 (MET)
* PR# 354 *
Subject: odd result of length() with factor arguments with NA
From: Rashid Nassar <rnassar@duke.edu>
Date: Tue, 30 Nov 1999 21:11:24 -0500 (EST)
* PR# 355 *
Subject: PRIVATE: Printing Problems
From: mlamias@umich.edu
Date: Wed, 1 Dec 1999 08:05:05 +0100 (MET)
* PR# 356 *
Subject: Error in plot.aov()
From: John Maindonald <john.maindonald@anu.edu.au>
Date: Thu, 02 Dec 1999 13:42:21 +1100
* PR# 357 *
Subject: filled.contour
From: steuer@statistik.uni-dortmund.de
Date: Fri, 3 Dec 1999 15:32:29 +01...
2000 Jan 31
1
Crosstabs?
Is there an equivalent in R to the crosstabs command S-Plus? I've been
searching for a while and can't seem to find anything.
Thanks.
Mark J. Lamias
Department of Statistics
Department of Political Science
Survey Methodology Program/Survey Research Center
Institute for Social Research - University of Michigan
426 Thompson Street, Room 315
Ann Arbor, Michigan 48104-2321
(734) 647-5381
2000 Apr 02
0
Expected Value of Residuals
Does anyone know a command to obtain the expected values of residuals under
normality? Better yet, is there a command to perform a correlation test for
normality (not Shapiro-Wilk Test)?
I've looked everywhere, and can't seem to find how to do this.
Thanks.
Mark J. Lamias
Department of Statistics
Department of Political Science
Survey Methodology Program/Survey Research Center
2000 Mar 07
3
Merging data.frames
On Tuesday, March 07, 2000 5:40 PM, Richard Bilonick wrote:
>I need to merge several data.frames into one data.frame. In S-Plus I would
>use
>"merge" but I don't see a merge command in R. What is the best way to
>accomplish
>this?
The easiest way to to this, I think, is as follows:
if you have several data frames, dataframe1, dataframe2, . . . , dataframen,
you