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...7/05/17184.html However, I'm not clear on how I might be able to use this info. to help myself. If anyone can provide any assistance, I would be eternally grateful. Oh, and I'm using R 2.4.1. Cheers, Mike -- Michael D. Rennie Ph.D. Candidate University of Toronto at Mississauga 3359 Missisagua Rd. N. Mississauga, ON L5L 1C6 Ph: 905-828-5452 Fax: 905-828-3792 www.utm.utoronto.ca/~w3rennie

...les, not by the row names (which are just typically 1:n, and is rarely informative). So, this is the solution I came up with based on what I can find out there currently. Looking forward to any thoughts or suggestions. -- Michael D. Rennie Ph.D. Candidate University of Toronto at Mississauga 3359 Missisagua Rd. N. Mississauga, ON L5L 1C6 Ph: 905-828-5452 Fax: 905-828-3792 www.utm.utoronto.ca/~w3rennie [[alternative HTML version deleted]]

Hi, My question is how do I gain control over what values the X and Y axis show. Below is a sample plot I have made and want the X axis to represent a time vector with values taking the form Q1.60, Q2.60, Q3.60...Q1.90..etc...Currently the X axis starts with value 0 and increases by 1 through the end of the sample. win.graph() matplot(v.0,log.diff.v.6,type="l",lty=1, col=2,

...stions on how to pull that off would be helpful. I'm certainly interested in any tips or tricks anyone might have for working with distance matrices, or any material that people can point me towards. Cheers, Mike -- Michael D. Rennie Ph.D. Candidate University of Toronto at Mississauga 3359 Missisagua Rd. N. Mississauga, ON L5L 1C6 Ph: 905-828-5452 Fax: 905-828-3792 www.utm.utoronto.ca/~w3rennie

...der of the terms of the model. However, a similar application using Manova(): m.an<-Manova(lm(Y~x1~x2)) m.an$F Returns NULL. So does any attempt at calling the headers in the MANOVA table. Any thoughts? Mike -- -- Michael D. Rennie Ph.D. Candidate University of Toronto at Mississauga 3359 Missisagua Rd. N. Mississauga, ON L5L 1C6 Ph: 905-828-5452 Fax: 905-828-3792 www.utm.utoronto.ca/~w3rennie

...t I'm using the code correctly as I was able to successfully reproduce an example in Quinn and Keough (2002) before I turned the code onto my own data. Looking forward to any thoughts or comments. Cheers, Mike -- Michael D. Rennie Ph.D. Candidate University of Toronto at Mississauga 3359 Missisagua Rd. N. Mississauga, ON L5L 1C6 Ph: 905-828-5452 Fax: 905-828-3792 www.utm.utoronto.ca/~w3rennie

...trying things like a$Mean or a[,2] but all return Error: incorrect number of dimensions probably because > length(a) [1] 1 Does anyone have any reccomendations on how to go any further here? Cheers, Mike -- Michael D. Rennie Ph.D. Candidate University of Toronto at Mississauga 3359 Missisagua Rd. N. Mississauga, ON L5L 1C6 Ph: 905-828-5452 Fax: 905-828-3792 www.utm.utoronto.ca/~w3rennie

I have a command that reads in some data: x <- read.csv("Sales2007.dat", header=TRUE) Then I try to organize the data: sc <- split(x, list(x$Category, x$SubCategory), drop=TRUE) Then I want to iterate through the data. I was able to get the following to run on the R console: for(i in 1:length(sc)) { sum(sc[[i]]$Quantity) } But notiing is primted on the console. I find

Dear R users, I have a txt file of the form 10092007 24.62 24.31 24.90 11092007 19.20 23.17 22.10 13092007 24.71 27.33 23.10 14092007 27.33 27.90 24.10 15092007 28.22 28.55 24.30 16092007 28.53 29.24 27.40 17092007 24.19 30.64 26.80 18092007 22.60 20.62 28.40 19092007 8.89 1.70 14.70 20092007 21.27 2.92 17.30 21092007 22.38 24.72 8.80 22092007 23.94 24.73 20.40 23092007 25.33 25.12 22.60