search for: minuty

Hi something like dcast(temp2, minuty~pokus) ? > dput(temp2) structure(list(pokus = structure(c(1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 7L, 7L, 8L, 8L ), .Label = c("T42", "T43", "T44", "T45", "T46", "T47", "T48", "T49&quo...

Well, ?factor does not say anything about this behaviour (assigning numeric code instead of level of factor). And actually if you do assignment for whole vector the result is different (vector in data frame is changed to factor). > temp2$fff[1]<-vec[1] > head(temp2,2) pokus minuty fff 1 T42 240 3 2 T42 300 <NA> > temp2$fff<-vec > head(temp2,2) pokus minuty fff 1 T42 240 c 2 T42 300 c > > is.factor(vec[1]) [1] TRUE I am not experieenced enough to explain what is happening but it is probably combination selection ?"[&quo...

HI all, Is it possible to use one column spread on multiple columns values. example spread( Key_col, value1:value7) spreading Key_col to variable value1, value2, ....... Value7 Please advise, Kind regards Mangalani Peter Makananisa (5786) South African Revenue Service (SARS) - HO +2782 456 4669 / +2712 422 7357 Please Note: This email and its contents are subject to our email legal notice

Ciao, ho recentemente acquistato un metodo molto costoso per guadagnare su Internet. Il metodo funziona davvero!!! Ora, in un giorno guadagno pi? denaro di quanto molti ne guadagnano in un mese. Le mie statistiche per oggi. Ho guadagnato _570 in 40 minuti. Fico, vero? Questo metodo funzioner? per circa 2 mesi. Io ho 2 inviti gratis; vorrei condividerne uno con te, solo non dirlo a

...lour=Species)) p+geom_point(aes(size=3)) } with different variations of y input but was not successful. In past I used qplot in similar fashion which worked for(i in names(mleti)[7:15]) print(qplot(sito, mleti1[,i], facets=~typ,ylab=i, geom=c("point", "line"), colour=ordered(minuty), data=mleti1)) So I wonder if anybody used ggplot in cycle and how to solve input of variables throughout cycle Thank you Petr

Your data frame fam contains factors. Turn it into character strings using fam$Family = as.character(fam$Family) and try again. It may be helpful if you read up on R's factors, see ?factor. HTH, Peter On Tue, Nov 21, 2017 at 2:14 PM, Glen Forister <gforister at gmail.com> wrote: > This is a simple problem, but a mystery to me. > I'm trying to grab $Family

This is a simple problem, but a mystery to me. I'm trying to grab $Family "Scelionidae" from one dataframe and put it into another dataframe occupied with NA in $Family. The result is a "158" ends up there instead of Scelionidae. Simply put fam$Family[1] <- least$Family[1] If I have made a mistake here, can somebody point it out. I've included the simple

Greetings, I have just been given a VPS with a fresh, minimal Centos 4.2 installation. When I ran "yum update" it went on updating some tenths of packages and signalled this error: Updating : perl ####################### [24/88] Updating : rpm-python ####################### [25/88] Updating : MAKEDEV

Dear Andrea. Your request seems vague. And also: be careful, even if some of the people reading the list understand italian you are expected to post your requests in english. In short: read the FAQ and at least "An introduction to R". But you seem to be lucky, on the CRAN you will find a document by Vito Ricci, in italian, about time series analysis:

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