search for: minning

I am attempting to write a code that will generate a win probability for a hockey team. To do this, I have a code built that will generate a number of random variables between two standard deviations, and then weight them and add them together. However, when I attempt to assign this code to a variable, any time I use the variable, it will always give me the same numbers instead of being random

Hello everyone, I am using *mlogit* to analyse my choice experiment data. I have *3 alternatives* for each individual and for each individual I have *9 questions*. I have a response from *516 individuals*. So it is a panel of 9*516 observations. I have arranged the data in long format (it contains 100 columns indicating different variables and identifiers). In mlogit I tried the following

Hi folks, The following are initial virtio-scsi + target vhost benchmark results using multiple target LUNs per vhost and multiple virtio PCI adapters to scale the total number of virtio-scsi LUNs into a single KVM guest. The test setup is currently using 4x SCSI LUNs per vhost WWPN, with 8x virtio PCI adapters for a total of 32x 500MB ramdisk LUNs into a single guest, along with each backend

Hi folks, The following are initial virtio-scsi + target vhost benchmark results using multiple target LUNs per vhost and multiple virtio PCI adapters to scale the total number of virtio-scsi LUNs into a single KVM guest. The test setup is currently using 4x SCSI LUNs per vhost WWPN, with 8x virtio PCI adapters for a total of 32x 500MB ramdisk LUNs into a single guest, along with each backend

Dear help-list, I would like to perform a linear regression on the log10 of the two vectors ov.mag.min and res.600nm. The slope and intercept of the regression I use to plot a wider range of ov.mag.min in a double log plot. For a linear regression on only tow points, wouldn't I expect the results for two.points.min to match pretty exactly res.600nm? It does not seem to be the case here.

I am trying to understand cut so I can divide a list of numbers into 10 group: 0-9.0 10-10.9 20-20.9 30-30.9, 40-40.9, 50-50.9 60-60.9 70-70.9 80-80.9 90-90.9 As I try to do this, I have been playing with the cut function. Surprising the following for applications of cut give me the exact same groups. This surprises me given that I have varied parameters include.lowest and right. Can someone

Hi, I have a fairly simple linear regression using the lm function. There are about 100 variables and 30,000 rows of data. It runs fine and produces a decent looking R2 value. I'm interested in performing a stepwise variable selection to see if things can be cleaned up a bit. Calling the step function returns ONE iteration (all the variables) and then stops. No errors are reported.

Dear Sirs, I am Professor at Indira Gandhi Krishi Vishwavidyalaya, Raipur, Chhattisgarh, India. While taking classes, I found the *by() *function producing following error when I use FUN=mean or median and some other functions, however, FUN=summary works. Given below is the output of the example I used on a built-in dataset "mtcars", along with error message reproduced herewith: >

Hi, This has been a problem since the xen-acpi-processor code was added to the kernel source. I wasn''t sure if the problem I was seeing was related to the old version (4.1.2) of Xen that I was using but now I''m on 4.2.0 and it still exists I thought I would check if I have a misconfiguration or if I have discovered a problem. My system is a dual AMD Opteron(tm) Processor

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Hello, Thank you ! I add server min protocol = SMB2_02 to smb.cnf All clients are now using SMB2_10 as minimum protocol version May you indicate me the difference between "client min protocol" and "server min protocol" ? "server min protocol" is to use on a domain member "client min protocol" is to use in which case ? Should I also set client min

Good day Im working with some coordinates, and want to create a PPP object, I found that error: > Datos=read.table("puntos_texto.txt",dec=".",sep="\t",header=T) > summary(Datos) id y x Min. : 1.0 Min. :1013581 Min. :1177842 1st Qu.: 821.2 1st Qu.:1014442 1st Qu.:1179658 Median

Have you read FAQ 7.31 recently, John? Your whole premise is flawed. You should be thinking of ranges [0,10), [10,20), and so on because numbers ending in 0.9 are never going to be exact. -- Sent from my phone. Please excuse my brevity. On April 16, 2016 7:38:50 PM PDT, John Sorkin <jsorkin at grecc.umaryland.edu> wrote: >I am trying to understand cut so I can divide a list of numbers

Jeff, Perhaps I was sloppy with my notation: I want groups >=0 <10 >=10 <20 >=20<30 ...... >=90 <100 In any event, my question remains, why did the four different versions of cut give me the same results? I hope someone can explain to me the function of include.lowest and right in the call to cut. As demonstrated in my example below, the parameters do not seem to alter

Hello, I have defined a new class > setClass("myclass", representation(min = "numeric", max = "numeric")) and want to write accessor functions, so that for > foo = new("myclass", min = 0, max = 1) > min(foo) # prints 0 > max(foo) # prints 1 At first i created a generic function for "min" > setGeneric("min",

I think you are not using the best function for what your intentions are. Try: > by(data=mtcars, INDICES=list(as.factor(mtcars$am)), FUN=colMeans) : 0 mpg cyl disp hp drat wt qsec vs 17.1473684 6.9473684 290.3789474 160.2631579 3.2863158 3.7688947 18.1831579 0.3684211 am gear carb 0.0000000

Hello, I get > summary(E) level nodes ave_nodes time Min. : 1 Min. : 1.00 Min. : 10.71 Min. : 0.0000 1st Qu.: 237414 1st Qu.: 2.00 1st Qu.: 19.70 1st Qu.: 0.0100 Median : 749229 Median : 3.00 Median : 27.01 Median : 0.0100 Mean : 767902 Mean : 49.85 Mean : 98.89 Mean : 0.2296 3rd

I have observed the following differences in the use of min/max functions between R and Splus (4.5) R (0.64.1): min(c(NA,NA,NA),na.rm=T) returns the following Warning in min(..., na.rm = na.rm) : no finite arguments to min/max; returning extreme. [1] 2147483647 S-Plus 4.5( Win32 edition) min(c(NA,NA,NA),na.rm=T) returns [1] NA The S-PLUS behaviour seems to be the right one Thanks,

Dear R help; I'll preface this by saying that the example I've provided below is pretty long, turgid, and otherwise a deep dive into a series of functions I wrote for a simulation study. It is, however, reproducible and self-contained. I'm trying to do my first simulation study that's quite big, and so I'll say that the output of this simulation as I'd like it to be is

How can I have both printout and saved results at the same time. The subroutine first return "out" and the printout gets printed, but not saved. I then run the "invisible" line. Results got saved and accessible but no printout. How can I have both printout and also have the results saved? Thank you! > dstat4 <- function(data,digits=3){ +?? Mean??? <-