search for: mestranda

Displaying 6 results from an estimated 6 matches for "mestranda".

2009 Mar 11
4
error.bars
Hi, I'm trying to use the function "error.bars", but the program don't find it, and I dont't found any package with this function. Is there some another functin to draw barplots with error bars? Sueli Rodrigues Eng. Agr?noma - UNESP Mestranda - USP/ESALQ PPG-Solos e Nutri??o de Plantas Fones (19)93442981 (19)33719762
2003 Sep 30
2
truncated multivariate normal
...of X to be non-negative (except the first), and the first dimension is strictly larger than zero. Example: X ~ NT_2(mu, Sigma), where mu=c(0.5, 0.5) and Sigma=c([120, 191], [191,154]), with X_1>0 and X_2>=0 Could anybody help me? Thanks in advanced. Juliana G. Cespedes Mestranda em Estat?stica e Experimenta??o Agron?mica Departamento de Ci?ncias Exatas - ESALQ/USP S?o Paulo - Brasil
2009 Apr 02
2
Scatter plot
Hi. How do I plot the straight line and r? in a scatter plot using a simple file x~y? Sueli Rodrigues Eng. Agr?noma - UNESP Mestranda - USP/ESALQ PPG-Solos e Nutri??o de Plantas Fones (19)93442981 (19)33719762
2009 Mar 06
2
Linear Regression
...006 2 0.681 9.916 3 0.789 10.271 3 0.702 10.076 3 0.692 9.990 3 0.646 9.779 3 0.620 9.749 3 0.608 9.708 4 1.052 11.779 4 0.941 11.249 4 0.881 10.140 4 0.824 10.052 4 0.790 9.859 . . . . . . . . . 80 0.499 9.819 Sueli Rodrigues Eng. Agr?noma - UNESP Mestranda - USP/ESALQ PPG-Solos e Nutri??o de Plantas Fones (19)93442981 (19)33719762
2009 Mar 05
1
Regressão linear
Ol?. Tenho um arquivo que a cada 6 linhas corresponde uma amostra da qual preciso dos coeficientes da regress?o linear. Como fa?o para que o programa distinga a cada 6 linhas como uma amostra e n?o calcule como um todo? Estou usando a fun??o: model=lm(y ~ x) Sueli Rodrigues Eng. Agr?noma - UNESP Mestranda - USP/ESALQ PPG-Solos e Nutri??o de Plantas Fones (19)93442981 (19)33719762
2012 May 15
9
help
1. Emma is performing an experiment that requires individual handling of some animals. The sizes of the animals are lognormally distributed: The natural logarithms of their sizes has a normal distribution with mean 3 and standard deviation 0.4. The time (in minutes) it takes to handle each animal is given by 10 + s · 1.5 + eε for animals with s ≤ 20 20 + s · 0.8 + eε for animals with s > 20