search for: menstruat

...ions are different from each other. In other words, I want the equivalent of Tukey's HSD test, but for proportions rather than anova. Here is one of the sets of number of "successes"; the denominator is 151 for all cases. Parents School Peers Church No one Menstruation 79 58 55 3 38 As proportions: > round(topics.sum[1,], digits=3) Parents School Peers Church No one 0.523 0.384 0.364 0.020 0.252 Intuitively, it looks like there are 3 or 4 groups that are different from each other, but is there a function that...