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...usly I tried with image() function [however there is also no option to put a color pallet :( ], there is a option 'zlim' to trim the not-required values. Is there any option in levelplot() function as well? I already gone through it's help file, however got nothing on that Megh Dal <megh700004@yahoo.com> wrote: Date: Sat, 15 Mar 2008 00:58:02 -0700 (PDT) From: Megh Dal <megh700004@yahoo.com> Subject: Re: How to create following chart for visualizing multivariate time series To: r-help@stat.math.ethz.ch Let me take an artifical matrix : dat = matrix(rnorm(200*200), 200, 2...

I have 2 vecros : x<-c(100,96,88,100,100,96,80,68,92,96,88,92,68,84,84,88,72,88,72,88) x1 = sample(x, 5, replace=FALSE) Now i want to get remaining values of vector "x" those are not member of vector "x1". Can anyone please tell me how to do that?

...g advice : ?plot.im Z <- setcov(owin()) plot(Z) .................... etc However I can not reproduce this example in my problem. How I can change my data matrix 'dat' to 'Z' ? If anyone show me some light it would be great for me. Regards, Megh Dal <megh700004@yahoo.com> wrote: Roy Mendelssohn <Roy.Mendelssohn@noaa.gov> wrote: Date: Thu, 28 Feb 2008 20:55:23 -0800 From: Roy Mendelssohn <Roy.Mendelssohn@noaa.gov> Subject: Re: [R] Fwd: Re: How to create following chart for visualizing multivariate time series To: Megh Dal <megh70000...

...lt;- seq(-4*pi, 4*pi, len=27) r <- sqrt(outer(x^2, y^2, "+")) image(x, y, r, col=gray((0:32)/32)) However my next problem to add a color pallet for color description [as shown in following link]. If anyone here tell me how to do that, it will be good for me. Regards, Megh Dal <megh700004@yahoo.com> wrote: Hi all, Can anyone here please tell me whether is it possible to produce a chart displayed in http://www.datawolf.blogspot.com/ in R for visualizing multivariate time series? If possible how? Regards, --------------------------------- ------------------...

Dear all, I have following 2 zoo objects. However when I try to merge those 2 objects into one, nothing is coming as intended. Please see below the objects as well as the merged object: > dat11 V2 V3 V4 V5 2010-10-15 13:43:54 73.8 73.8 73.8 73.8 2010-10-15 13:44:15 73.8 73.8 73.8 73.8 2010-10-15 13:45:51 73.8 73.8 73.8 73.8 2010-10-15 13:46:21 73.8 73.8 73.8 73.8

I have following dataset: > res [,1] [,2] [,3] [1,] 1946 4 1.27 [2,] 1946 5 1.27 [3,] 1946 6 1.27 [4,] 1946 7 1.27 [5,] 1946 8 1.52 [6,] 1946 9 1.52 [7,] 1946 10 1.52 [8,] 1946 11 1.52 [9,] 1946 12 1.62 [10,] 1947 1 1.62 [11,] 1947 2 1.62 [12,] 1947 3 1.62 [13,] 1947 4 1.87 [14,] 1947 5 1.87 [15,] 1947 6 1.87 Now I write following code

[My previous message rejected, therefore I am sending same one with some modification] I have 3 vectors with object name : dat1, dat2, dat3 Now I want to create a loop, like : for (i in 1:3) { cat(sd(dati)) } How I can do this in R? Regards,

Is there any R function to calculate automatically the last day of a particular month? For example "sep2009" should be converted to last day of September of 2009? Thanks -- View this message in context: http://www.nabble.com/How-to-get-last-day-of-a-month--tp25425645p25425645.html Sent from the R help mailing list archive at Nabble.com.

Forgot to send one copy to R help. Sorry Megh Dal <megh700004@yahoo.com> wrote: Date: Wed, 7 May 2008 02:45:09 -0700 (PDT) From: Megh Dal <megh700004@yahoo.com> Subject: Re: [R] Solution of function To: Berwin A Turlach <berwin@maths.uwa.edu.au> Hi Berwin, Thanks for having look on my problem. However on ipop() function I see followin...

I have following " 1975 01 7711.16" Here I need to identify where the <space> is there and then concatenate rest of the digits without <space>, i.e. I want to have "1975017711.16". Is there any R function? Regards,

Dear all, I need to download an excel file from net, on which I have address like http://www.2shared.com/file/MMSMWv4B/MyData.html. Can I somehow directly download this file into my R workbook? Thanks, [[alternative HTML version deleted]]

Hi all, can you please clarify me what is the wrong with following codes : set.seed(30) z = matrix(rnorm(10), 5, 2) apply(z, 1, function(x) sum(z[x,1]*1, z[x,2]*3)) However I can not get the desired result. For example, "sum(z[1,1]*1, z[1,2]*3)" gives -5.822442 which is actually correct. Am I missing something in apply() function? Regards, -- View this message in context:

Please consider following string: MyString <- "ABCFR34564IJVEOJC3434" Here you see that, there are 4 groups in above string. 1st and 3rd groups are for english letters and 2nd and 4th for numeric. Given a string, how can I separate out those 4 groups? Thanks for your time [[alternative HTML version deleted]]

...explicit description of all slots of it's superclass? If yes why? In my understanding, all defined law for super-class should be inherited by it's sub-class, therefore no need to define again. I would be really grateful if someone clarify those. Thanks --- On Fri, 7/30/10, Megh Dal <megh700004 at yahoo.com> wrote: > From: Megh Dal <megh700004 at yahoo.com> > Subject: Having problem to define a subclass, please help me > To: r-help at stat.math.ethz.ch > Date: Friday, July 30, 2010, 4:46 PM > Here I am having problem to define a > subclass, specially if I defin...

Hi, I have created a list object like that : x = vector("list") for (i in 1:5) x[[i]] = rnorm(2) x Now I want to do two things : 1. for each i, I want to do following matrix calculation : t(x[[i]]) %*% x[[i]] i.e. for each i, I want to get a 2x2 matrix 2. Next I want to get x[[1]] + x[[2]] +.... I did following : res=vector("list"); res = sapply(x, function(i) t(x[[i]]) %*%

Dear all, Please forgive me if there is a duplicate post; my previous mail perhaps didnt reach the list....... Let say I have following time series library(zoo) > dat1 <- zooreg(rnorm(10), start=as.Date("2010-01-01"), frequency=1) > dat1[c(3, 7,8)] = NA > dat1 2010-01-01 2010-01-02 2010-01-03 2010-01-04 2010-01-05 2010-01-06 2010-01-07 2010-01-08 2010-01-09

Dear all R users, I have a small doubt about panel data analysis. My basic understanding on Panel data is a type of data that is collected over time and subjects. Vector Autoregressive Model (VAR) model used on this type of data. Therefore can I say that, one of statistical tools used for analysis of panel data is VAR model? If you clarify my doubt I will be very grateful. Thanks and regards,

Can anyone please tell whether there is any R function to act as "VEC" and "VECH" operator on Matrix? Yes of course, I can write a user-defined-function for that or else, I can put dim(mat) <- NULL. However I am looking for some R function. Your help will be highly appreciated. Regards, -- View this message in context:

Hi, I am trying to create a vector of length 10 (say), wherein each element will be average of random sample of size 100, from a distribution, say Normal. Can anyone please tell me without creating a "for" loop, how I can do that? Regards, -- View this message in context: http://www.nabble.com/Alternate-to-for-loop-tp22035954p22035954.html Sent from the R help mailing list archive at

Hi, I have following kind of dataset (all are dates) in my Excel sheet. 09/08/08 09/05/08 09/04/08 09/02/08 09/01/08 29/08/2008 28/08/2008 27/08/2008 26/08/2008 25/08/2008 22/08/2008 21/08/2008 20/08/2008 18/08/2008 14/08/2008 13/08/2008 08/12/08 08/11/08 08/08/08 08/07/08 However I want to use R to compile those data to make all dates in same format. Can anyone please tell me any automated way