Displaying 2 results from an estimated 2 matches for "median3".
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median
2003 Oct 29
3
long algo
...(the inevitable however), I am finding it very
slow for one of my operations:
it s basically an itertation over i and j in a pretty
big table (4* 4608). It takes 30 minutes!!!!
Thanks
Ps:if it can help here is the source:
median1<-matrix(nrow=4608,ncol=1)
median2<-matrix(nrow=4608,ncol=1)
median3<-matrix(nrow=4608,ncol=1)
median4<-matrix(nrow=4608,ncol=1)
v<-c(18,19,20,21,23)
for (i in 0:11)
{
for (j in 1:384)
{
median1[j+(i*384),]<-puce[j+(i*384),5]+median(puce[v+384*i,2]-puce[v+384*i,5])
median2[j+(i*384),]<-puce[j+(i*384),19]+median(...
2005 May 25
3
Speex on TI C6x, Problem with TI C5x Patch
...st->voc_m2=st->voc_mean=0;
st->voc_offset=0;
st->dtx_enabled=0;
#ifdef ENABLE_VALGRIND
VALGRIND_MAKE_READABLE(st, (st->stack-(char*)st));
#endif
return st;
}
void nb_decoder_destroy(void *state)
{
DecState *st;
st=(DecState*)state;
speex_free(state);
}
#define median3(a, b, c) ((a) < (b) ? ((b) < (c) ? (b) : ((a) < (c) ? (c) :
(a))) : ((c) < (b) ? (b) : ((c) < (a) ? (c) : (a))))
static void nb_decode_lost(DecState *st, spx_word16_t *out, char *stack)
{
int i, sub;
VARDECL(spx_coef_t *awk1);
VARDECL(spx_coef_t *awk2);
VARDECL(spx_coef...