Displaying 2 results from an estimated 2 matches for "measurment_num_m".
Did you mean:
measurment_num
2010 Feb 03
1
Additional field data collection
This is a subset of a much larger dataframe. I would like to be able
to automate finding the pair of x, y coordinates where the line
crosses zero agian
x <- (structure(list(bankfull_depths_m = c(0, 0.17, 0.38, 0.37, 0.36,
0.39, 0.47, 0.48, 0.19, 0.05, -0.05, -0.09), measurment_num_m = c(0.2,
0.4, 0.6, 0.8, 1, 1.2, 1.4, 1.6, 1.8, 2, 2.2, 2.4)), .Names =
c("bankfull_depths_m",
"measurment_num_m"), class = "data.frame", row.names = 97:108))
qplot(measurment_num_m, bankfull_depths_m, data=x)
in this case it is 2.1, 0
I need a way to process a whole...
2010 Feb 04
1
for loop with if statment problem
...L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L), .Label = c("", "changed from 1.2 to 1.02", "changed from 1.4 to 1.04",
"changed from 1.6 to 1.06", "marked as no bankfull correction-I don't
know if this is correct"
), class = "factor"), measurment_num_m = c(0, 0.2, 0.4, 0.6,
0.8, 1, 1.2, 1.4, 1.6, 1.8, 2, 2.2, 2.4, 2.6, 2.8, 3, 3.2, 3.4,
3.6, 3.8, 4, 0, 3.8, 3.6, 3.4, 3.2, 3, 2.8, 2.6, 2.4, 2.2, 2,
1.8, 1.6, 1.4, 1.2, 1, 0.8, 0.6, 0.4, 0.2, 0, 2, 1.8, 1.6, 1.4,
1.2, 1, 0.8, 0.6, 0.4, 0.2, 0, 2.8, 2.6, 2.4, 2.2, 2, 1.8, 1.6,
1.4, 1.2, 1, 0.8, 0.6,...