Displaying 20 results from an estimated 2834 matches for "meaningfully".
2012 Feb 29
3
Cannot use negative argument in function
Hi,
today i wrote a function in R of the type:
index.refraction <- function(Temp,Press, RH, CO2)
When i try to plug a negative number in Temp, i got this type of error:
"
n <- index.refraction(Temp= -40,100,80,CO2)
Messages d'avis :
1: In Ops.ordered(left, right) : '-' is not meaningful for ordered factors
2: In Ops.factor(left, right) : - not meaningful for factors
3:
2010 Sep 05
1
Warning messages: not meaningful for factors
Dear Experts,
I need to include the repeated structure in our data set object,
recall.sums.df, before using gls function.
Thus I used groupedData.
But I encountered error messages which may mean '*' is not not meaningful
factor.
Please let me know what I have to do.
Thanks,
Jeong
> recall.sums.df[0:10, ]
recall.values recall.ind subj replication hemi region group
1 17.515
2010 Dec 27
1
matrix looping accessing previous column
Hi,
I have a matrix with numbers and character. I want to evaluate each cell and
change the value of the cell before it depending on the evaluation. My
evaluation: if a cell had the word "down" change the cell preceding it to a
negative number by multiplying that value by a -1. I am have trouble going
back on clumn to make this change. I'm receiving an error on the j-1 part,
and the
2002 Nov 26
4
[NB] lm problems
Hi,
I have probably overlooked something obvious, but could anybody
help me with following, please?
Trying to make regression analysis. I have a huge dataframe with
results from National Opinion Survey on Crime and Justice
(www.abacon.com/fox/) with two variables G5 and N3 which are
imported to R as ordered factors:
> levels(noscj$G5)
[1] "Strongly agree" "Agree"
2006 Jan 15
8
/ Operator not meaningful for factors
Folks,
I have a very basic question. The solution eludes me perhaps because
of my own lack of creativity. I am not attaching a fully reproducible
session because the issue may well be becuase of the way the data file
is, and the data file is large (and I don't know whether I can legally
distribute it). If people can suggest things that might be wrong in my
data or the way that I am reading it,
2011 Nov 10
4
Error in Summary.factor(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 4L, : max not meaningful for factors
Hello,
Beginner, sorry if this is wasting anyone's time, but have been working on
this for a couple of days now, think it should have take a few hours!
The Problem:
Error in Summary.factor(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 4L, :
max not meaningful for factors
I have tried to re-arrange and check formula. I am working in SIAR, and
cannot get model1 to run because of the error
2009 Aug 20
2
what is the meaning of this error
Error in Math.factor(c(2L, 1L, 1L, 1L, 1L, 3L, 1L, 1L, 1L, 1L, 1L, 1L, :
log not meaningful for factors
In addition:Warning messages:
1: In Ops.factor(LRUpBound, LRLowBound) : * not meaningful for factors
2: In Ops.factor(TransitCoefStdDev, TransitCoefMean) :
/ not meaningful for factors
[[alternative HTML version deleted]]
2012 Oct 04
1
Ops.factor(point1, point2) : - not meaningful for factors
Hi, can anyone help me in this problem :(. I am a total beginner in R
software. It took me 2 days just to look into this problem. Due to this
problem. I cant do looping. i want to find the distance between x and DSi
> DSi
i Si
1 1 (5, 20)
2 2 (20, 2)
3 3 (25, 32)
4 4 (8, 39)
5 5 (10, 17)
6 6 (35, 20)
7 7 (38, 10)
> str (DSi)
'data.frame': 7 obs. of 2 variables:
$ i
2008 Jun 04
1
"& not meaningful for factors"
I am trying to define groupings from levels of factor variables and this the warning message that R give
"& not meaningful for factors".
The nature of my task is this. I have a variable stage which has the levels (1B, 2A, 2B) - these are the AJCC TNM stages of cancer, and another variable diameter with factor levels ("=< 4", "4 - 6.5, > 6.5; limit values are
2008 Dec 04
1
Formula parsing and updating
Hi all,
I can't come over a problem with formula. Suppose I have a coxmod model
with the following formula:
> somemod$formula
Surv(lebzeit, tot == 1) ~ sex + (alter >= 65) + diff3k + zelltyp_k_c +
q_nuc_3k + kar_k80_g80 + stadium
and I want to drop the stadium explanatory variable from the model with
> update(somemod, ". ~ . - stadium")
I get the following messages:
2003 Jan 02
1
aggregate: "sum" not meaningful for factors
Dear all,
I try to summarise my data per category using aggregate, but for some
reason I get the error message "sum" not meaningful for factors even though
my vector is numeric. The data set is shown below.
Could someone please give a hint.
Thanks in advance!
Sincerely,
Tord
> names(test)
[1] "ObjektID" "tallstubbyta"
> is.factor(test$ObjektID);
2005 Jun 16
2
[LLVMdev] Useless/Mis-placed Tests?
For some time now the tests in llvm-test/SingleSource/Regression and
llvm-test/SingleSource/UnitTests have been producing no meaningful
performance data other than "working". I think one of two things should
be done, on a case-by-case basis:
1. Tests that are clearly simple, quick running tests should be moved
into the llvm/test/Regression directory and made part of the deja-gnu
suite
2011 Jan 05
1
Minimum of an ordered factor
Hi everybody,
Is there a particular reason, why this code does not work as intended:
z <- factor(LETTERS[1:3], ordered = TRUE)
u <- 4:6
min(z[u > 4])
Error in Summary.factor(2:3, na.rm = FALSE) :
min not meaningful for factors
I agree that min is indeed not meaningful for not ordered factors, but
it makes sense for ordered factors. Especially since
z[3] <
2003 Dec 22
1
[R] lattice: levelplot: error: min not meaningful for factor (PR#6005)
R 1.8.1:
___COMMAND____________________________________________
levelplot( yield ~ year * variety | site, barley )
___ERROR_MESSAGE______________________________________
Error in Summary.factor(..., na.rm = na.rm) :
"min" not meaningful for factors
___COMMENT____________________________________________
levelplot( yield ~ as.numeric(year) * as.numeric(variety) | site,
2018 Mar 22
3
How do I include a factor in a groupedData object? Meaning and use of inner and outer parameters
Windows 10 64-bit, R-Studio, R version 3.4.3
Several questions relating to groupedData:
(1) I am trying to create a groupedData object that can be used to run an analysis that I have been able to urn using lmer. When I include the interaction terms in the groupedData opbject I get an error message stating that + is not meaningful for factors. How do I include factors in my model? See code and
2008 May 27
2
Help with Writing Meaningful Specs
Hello all,
In yet another attempt to learn Ruby on Rails and Rspec I have started
writing a simple life streaming app with will aggregate feeds from several
places and save them in a database for later use.
An internet search eventually led me to the following method for looping
through the feeds in the database, getting the contents of the URL and then
passing this into another model to prepare
2010 Dec 14
1
rpart - how to estimate the “meaningful” predictors for an outcome (in classification trees)
Hi dear R-help memebers,
When building a CART model (specifically classification tree) using rpart,
it is sometimes obvious that there are variables (X's) that are meaningful
for predicting some of the outcome (y) variables - while other predictors
are relevant for other outcome variables (y's only).
*How can it be estimated, which explanatory variable is "used" for which of
2000 Apr 07
1
lme questions (was difference between splus and R)
> Date: Fri, 7 Apr 2000 09:55:08 -0400 (EDT)
> From: Faheem Mitha <faheem at email.unc.edu>
[I have given a more meaningful subject line.]
> On Fri, 7 Apr 2000, Prof Brian D Ripley wrote:
>
> > On Thu, 6 Apr 2000, Faheem Mitha wrote:
> >
> > > I'm running splus 5 on a solaris platform remotely, and running R on linux
> > > on my home machine.
2015 Sep 29
3
making object.size() more meaningful on environments?
Hi,
Currently object.size() is not very useful on environments as it always
returns 56 bytes, no matter how big the environment is:
env1 <- new.env()
object.size(env1) # 56 bytes
env2 <- new.env(hash=TRUE, size=75000000L)
object.size(env2) # 56 bytes
env3 <- list2env(list(a=runif(25000000), L=LETTERS))
object.size(env3) # 56 bytes
This makes it pretty useless on
2015 Sep 29
0
making object.size() more meaningful on environments?
Herve,
The problem then would be that for A a refClass whose fields take up N
bytes (in the sense that you mean), if we do
B <- A
A and B would look like the BOTH take up N bytes, for a total of 2N,
whereas AFAIK R would only be using ~ N + 2*56 bytes, right?
~G
On Tue, Sep 29, 2015 at 2:42 PM, Herv? Pag?s <hpages at fredhutch.org> wrote:
> Hi,
>
> Currently object.size()