Displaying 3 results from an estimated 3 matches for "meanc".
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2001 Apr 26
1
list.files wildcard
Hello all,
I have a simple question:
I have filenames that look like these:
"n031ku09.10msmeanc" "n031ku10.10msmeanc" "n031ku11.10msmeanc"
[22] "n031ku12.10msmeanc" "n031ti01.10msmeanc" "n031ti02.10msmeanc"
I also have a set of the same without the "c" at the end.
When I run list.files(".", pattern="*ku[01-30].m...
2010 Apr 05
3
bootstrap confidence intervals, non iid
hello,
i need to calculate ci's for each of 4 groups within a dataset, to be able
to infere about differences in the variable "similarity". the problem is
that data within groups is dependent, as assigned by the blocking-factor
"site". my guess was to use a block bootstrap but samples within in these
blocks / sites are not of same length. i was not able to find a method to
2006 Oct 18
6
new R-user needs help
Dear all,
I have a dataset
Exp name id x1 x2 x3 x4 x5
1 a 1 23 24 23 22 30
1 b 2 25 26 27 23 24
1 c 3 32 19 23 25 28
2 a 4 28 32 24 26 27
2 b 5 23 24 25 26 28
2 c 6 23 31 30 38 23
3 a 7 24 25 31 27 29
3 b 8 28 25 26 32 28
3 c 9 21 31 28 23 29
where each name a,b and c is repeated three times.
Now I want to calculate the the averages of