Displaying 7 results from an estimated 7 matches for "meanb".
Did you mean:
means
2017 Jul 13
2
about plotting a special case
...probs=c()), rather than DF1$A? Also, how to add a legend
for both points DF1 and DF2?
On Wed, Jul 12, 2017 at 8:25 PM, Jim Lemon <drjimlemon at gmail.com> wrote:
> Hi lily,
> Here is the first plot:
>
> plot(DF1$A,DF1$B,pch=19,col="red")
> meanA<-mean(DF1$A)
> meanB<-mean(DF1$B)
> points(meanA,meanB,pch=18,col="red")
> q1090<-quantile(DF1$B,probs=c(0.1,0.9))
> library(plotrix)
> dispersion(meanA,meanB,q1090[2],q1090[1],
> intervals=FALSE,col="red")
>
> The same code will work for a second data frame, except that...
2017 Jul 13
0
about plotting a special case
...21 52
>> 61 23 50
>> 40 19 51
>> 58 18 57
>> 38 24 58
>> 37 27 53",header=TRUE)
>> plot(DF1$A,DF1$B,xlim=range(c(DF1$A,DF2$A)),
>> ylim=range(c(DF1$B,DF2$B)),pch=19,col="red")
>> meanA<-mean(DF1$A)
>> meanB<-mean(DF1$B)
>> points(meanA,meanB,pch=18,col="red")
>> q1090<-quantile(DF1$B,probs=c(0.1,0.9))
>> plotCI(meanA,meanB,ui=q1090[2],li=q1090[1],err="x",
>> add=TRUE,col="red")
>> points(DF2$A,DF2$B,pch=19,col="green")
>&...
2017 Jul 13
0
about plotting a special case
Hi lily,
Here is the first plot:
plot(DF1$A,DF1$B,pch=19,col="red")
meanA<-mean(DF1$A)
meanB<-mean(DF1$B)
points(meanA,meanB,pch=18,col="red")
q1090<-quantile(DF1$B,probs=c(0.1,0.9))
library(plotrix)
dispersion(meanA,meanB,q1090[2],q1090[1],
intervals=FALSE,col="red")
The same code will work for a second data frame, except that you would
use "points" i...
2017 Jul 13
2
about plotting a special case
Hi R users,
I have a question about plotting. There is the dataframe below, while each
row represents a record. If I want to plot on a A-B plot, i.e., x-axis
represents A, while y-axis represents B values. However, I want to plot the
mean value from records 1-10 as one point, while the 10th and 90th
percentiles represent the error bars, such as one point in the attached
example. I don't know
2012 Feb 16
1
how to get r-squared for a predefined curve or function with "other" data points
...282673 NA
2 SE . 0.1279981 0.1937197 NA
---
by averaging parameters a and b of the curve, i create a "mean curve" that
is added to the plot (red curve in the attached image).
http://r.789695.n4.nabble.com/file/n4394609/conductivity-curve.gif
---
meana <- average[1,"a"]
meanb <- average[1,"b"]
curve(100/(1+exp(meana*(x-meanb))), col=2, lwd=2, add = TRUE)
---
and now here's my problem:
i'd like to calculate R squared for all points on that mean curve.
since i have to average the curve parameters, i loose the curve's residuals
that are stored in...
2010 Apr 05
3
bootstrap confidence intervals, non iid
hello,
i need to calculate ci's for each of 4 groups within a dataset, to be able
to infere about differences in the variable "similarity". the problem is
that data within groups is dependent, as assigned by the blocking-factor
"site". my guess was to use a block bootstrap but samples within in these
blocks / sites are not of same length. i was not able to find a method to
2006 Oct 18
6
new R-user needs help
Dear all,
I have a dataset
Exp name id x1 x2 x3 x4 x5
1 a 1 23 24 23 22 30
1 b 2 25 26 27 23 24
1 c 3 32 19 23 25 28
2 a 4 28 32 24 26 27
2 b 5 23 24 25 26 28
2 c 6 23 31 30 38 23
3 a 7 24 25 31 27 29
3 b 8 28 25 26 32 28
3 c 9 21 31 28 23 29
where each name a,b and c is repeated three times.
Now I want to calculate the the averages of