Displaying 1 result from an estimated 1 matches for "meanagem".
Did you mean:
meanage
2004 May 27
1
Getting the same values of adjusted mean and standard errors as SAS
...for Gender
using values from predict. So I attempted to get them directly from the
residuals as follows. The data is at the end
of the email. While there is a match for the males there is a large
difference for the females indicating that what I am doing is wrong.
#
meanAge <- mean(dd$Age)
meanAgeM <- mean(dd$Age[d$Gender=="M"])
meanAgeF <- mean(dd$Age[d$Gender=="F"])
# determine adjusted means for the males and females at meanAge using
predict
# set up data frame to get predicted values at meanAge
evalDF <- data.frame(Age = meanAge, Gender = c("F",&q...