Displaying 1 result from an estimated 1 matches for "meanagef".
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meanage
2004 May 27
1
Getting the same values of adjusted mean and standard errors as SAS
...to get them directly from the
residuals as follows. The data is at the end
of the email. While there is a match for the males there is a large
difference for the females indicating that what I am doing is wrong.
#
meanAge <- mean(dd$Age)
meanAgeM <- mean(dd$Age[d$Gender=="M"])
meanAgeF <- mean(dd$Age[d$Gender=="F"])
# determine adjusted means for the males and females at meanAge using
predict
# set up data frame to get predicted values at meanAge
evalDF <- data.frame(Age = meanAge, Gender = c("F","M"),
Group = c("1NC",&quo...