search for: meana

Hi, I need to sample randomly my dataset for 1000 times. The sample need to be the 80%. I know how to do that, my problem is that not only I need the 80%, but I also need the corresponding 20% each time. Is there any way to do that? Alternatively, I was thinking to something like setdiff () function to compare my 80% sample to the original dataset and obtain the corresponding 20%, unfortunately

Dear all, Sorry to bother you with such a stupid question, but I just cannot find the solution to my problem. I'd like to use matrix multiplication for meanA and factorial 3. I use the command meanA%*%factorial 3. But everything I get is: Error in factorial3 %*% A : non-conformable arguments I know that the number of the columns of the first vector has to be the same number of rows of the second vector to be able to use matrix multiplication, but th...

...1090 <- quantile(DF1$B, probs=c()), rather than DF1$A? Also, how to add a legend for both points DF1 and DF2? On Wed, Jul 12, 2017 at 8:25 PM, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi lily, > Here is the first plot: > > plot(DF1$A,DF1$B,pch=19,col="red") > meanA<-mean(DF1$A) > meanB<-mean(DF1$B) > points(meanA,meanB,pch=18,col="red") > q1090<-quantile(DF1$B,probs=c(0.1,0.9)) > library(plotrix) > dispersion(meanA,meanB,q1090[2],q1090[1], > intervals=FALSE,col="red") > > The same code will work for a seco...

...47 25 53 >> 70 21 52 >> 61 23 50 >> 40 19 51 >> 58 18 57 >> 38 24 58 >> 37 27 53",header=TRUE) >> plot(DF1$A,DF1$B,xlim=range(c(DF1$A,DF2$A)), >> ylim=range(c(DF1$B,DF2$B)),pch=19,col="red") >> meanA<-mean(DF1$A) >> meanB<-mean(DF1$B) >> points(meanA,meanB,pch=18,col="red") >> q1090<-quantile(DF1$B,probs=c(0.1,0.9)) >> plotCI(meanA,meanB,ui=q1090[2],li=q1090[1],err="x", >> add=TRUE,col="red") >> points(DF2$A,DF2$B,pch=...

Hi lily, Here is the first plot: plot(DF1$A,DF1$B,pch=19,col="red") meanA<-mean(DF1$A) meanB<-mean(DF1$B) points(meanA,meanB,pch=18,col="red") q1090<-quantile(DF1$B,probs=c(0.1,0.9)) library(plotrix) dispersion(meanA,meanB,q1090[2],q1090[1], intervals=FALSE,col="red") The same code will work for a second data frame, except that you would us...

Hi R users, I have a question about plotting. There is the dataframe below, while each row represents a record. If I want to plot on a A-B plot, i.e., x-axis represents A, while y-axis represents B values. However, I want to plot the mean value from records 1-10 as one point, while the 10th and 90th percentiles represent the error bars, such as one point in the attached example. I don't know

...b R2 1 Mean 3 1.6417389 -3.1282673 NA 2 SE . 0.1279981 0.1937197 NA --- by averaging parameters a and b of the curve, i create a "mean curve" that is added to the plot (red curve in the attached image). http://r.789695.n4.nabble.com/file/n4394609/conductivity-curve.gif --- meana <- average[1,"a"] meanb <- average[1,"b"] curve(100/(1+exp(meana*(x-meanb))), col=2, lwd=2, add = TRUE) --- and now here's my problem: i'd like to calculate R squared for all points on that mean curve. since i have to average the curve parameters, i loose the cur...

hello, i need to calculate ci's for each of 4 groups within a dataset, to be able to infere about differences in the variable "similarity". the problem is that data within groups is dependent, as assigned by the blocking-factor "site". my guess was to use a block bootstrap but samples within in these blocks / sites are not of same length. i was not able to find a method to

...text include => extensions exten => _9.,1,Dial(Zap/1/${EXTEN:1}) zapata.conf =========== [channels] ; TDM40B card signalling=fxo_ks context=internal channel => 1-4 iax.conf ======== [1000] type=friend context=internal disallow=all allow=gsm host=dynamic username=1000 secret=1000 so this meanas the four extensions plugged in to the TDM40B's all will fall into the "internal" extension, as does the IAX user "1000". So if you have additional office staff at extensions "5001", "5002" and "5003" connected via SIP, in sip.conf you'd...

Dear all, I have a dataset Exp name id x1 x2 x3 x4 x5 1 a 1 23 24 23 22 30 1 b 2 25 26 27 23 24 1 c 3 32 19 23 25 28 2 a 4 28 32 24 26 27 2 b 5 23 24 25 26 28 2 c 6 23 31 30 38 23 3 a 7 24 25 31 27 29 3 b 8 28 25 26 32 28 3 c 9 21 31 28 23 29 where each name a,b and c is repeated three times. Now I want to calculate the the averages of