search for: maxcost

...ng budget of 10, portfolio cost 6, cheapest availabe stock 3 despite the diff variable being negative. Any ideas? y<-1-new.set[,6:26] remain<-y*data3[,5] minn<-matrix(0,nrow(remain),1) for(q in 1:nrow(remain)) { remainc<-remain[q,] minn[q,]<-min(remainc[which(remainc>0)]) } maxcost<-matrix(150,nrow(new.set),1) diff<-maxcost[,1]-new.set[,5]-minn[,1] new.set<-subset(new.set,diff<0) -- View this message in context: http://r.789695.n4.nabble.com/Bug-in-my-code-finding-nonzero-min-tp4637399.html Sent from the R help mailing list archive at Nabble.com.