search for: mary

Hi, there, I have a simple data manipulation question for you. Thank you for your help! Suppose that I have this data about people appearing in a class Mary Mary Mary Sam Sam John John John John Then I want to find out what exact time(s) the student appears at the moment such as Mary 1 Mary 2 Mary 3 Sam 1 Sam 2 John 1 John 2 John 3 John 4 the fifth row shows tha Sam show the second times at the that moment. How can I manipulate the data in this wa...

...issing something very elementary here, and I don't seem to get it from the help pages of the ave, seq and seq_along functions, so I wonder if you could offer a quick help. To use an example from an earlier post on this list, I have a dataframe of this kind: dat = data.frame(name = rep(c("Mary", "Sam", "John"), c(3,2,4))) dat$freq = ave(seq_along(dat$name), dat$name, FUN = seq_along) dat name freq 1 Mary 1 2 Mary 2 3 Mary 3 4 Sam 1 5 Sam 2 6 John 1 7 John 2 8 John 3 9 John 4 What I need is another column assigning a number to ea...

Hi, R function aggregate can only take summary stats functions, can I aggregate text columns? For example, for the dataframe below, > a <- rbind(data.frame(id=1, name='Tom', hobby='fishing'),data.frame(id=1, name='Tom', hobby='reading'),data.frame(id=2, name='Mary', hobby='reading'),da...

Hello! I have a matrix a with 2 variables (see below) that contain character strings. I need to create a 3rd variable that contains True if the value in column x is equal to the value in column y. The code below does it. a<-data.frame(x=c("john", "mary", "mary", "john"),y=c("mary","mary","john","john")) a$x<-as.character(a$x) a$y<-as.character(a$y) a$equal<-NA for(i in 1:nrow(a)) {a[i,3]<-a[i,1] %in% a[i,2]} I was wondering if one can do it faster, without doing it row-...

Hi, I have a data frame with 3 columns: ID, year and score. How can I select for each unique ID, the year that has the max score? For example, for data frame ID, year, score tom, 1995, 88 rick, 1994, 90 mary, 2000, 97 tom, 1998, 60 mary, 1998,100 I shall have ID, year, score tom, 1995, 88 rick, 1994, 90 mary, 1998,100 Thanks, Richard [[alternative HTML version deleted]]

...rrectly but the next recipients do not. ?ltmp apparently tries to create a link from the subsequent recipients' mail store to the first recipient mail store and fails. This returns 451 smtp codes to the sender which then resends at some later time. Please see below for users jerry, steve, and mary. The message to jerry gets written but not steve or mary: ul 27 11:24:41 testmailserver dovecot: lmtp(12412): Debug: none: root=, index=, control=, inbox= Jul 27 11:24:41 testmailserver dovecot: lmtp(12412): Connect from 143.112.53.4 Jul 27 11:24:41 testmailserver dovecot: lmtp(12412): Debug: aut...

Hallo, I have got an existing data frame and want to add a new column. The existing data frame was created like this: > df <- rbind( c("Fred", "Mary", 4), c("Fred", "Mary", 7), + c("Fred", "Mary", 9), c("Barney", "Liz", 3), + c("Barney", "Liz", 5) ) > df <- data.frame(df) > colnames(df) <- c("Father", "Mo...

Hello, I have an unbalanced panel data set that looks like: ID,YEAR,HEIGHT Tom,2007,65 Tom,2008,66 Mary,2007,45 Mary,2008,50 Harry,2007,62 Harry,2008,62 James,2007,68 Jack,2007,70 Jordan,2008,72 That is, James, Jack, and Jordan are missing a YEAR. Is there any command that will "fill in" the missing YEAR such that the end result will be balanced and look like: ID,YEAR,HEIGHT Tom,2007,65...

I will be out of the office starting Wed June 9th and returning Wed June 16th. Please contact Mary at mary at accessgate.net cell 407-267-1463 or Jonathan at jsnyder at accessgate.net cell 407-267-0056 or call our main number 888-227-9337.

...ooks Done No role scripts were specified. Skipping Creating Xen configuration file Done Setting up root password Enter new UNIX password: Retype new UNIX password: passwd: password updated successfully All done Logfile produced at: /var/log/xen-tools/Marie-DHCP.log Installation Summary --------------------- Hostname : Marie-DHCP Distribution : squeeze IP-Address(es) : 192.168.1.3 RSA Fingerprint : 25:46:6c:76:3a:39:fc:7a:bb:7b:31:33:9c:7f:30:09 Root Password : N/A A # locate Marie shows: root@debian:/home/dorian/Téléchargements/xen-4.2.1# locate Marie /de...

Dear people from the R help list, I have a question that I can't get my head around to start answering, that is why I am writing to the list. I have data in a format like this (tabs might look weird): John A1 1 0 1 John A2 1 1 1 John A3 1 0 0 Mary A1 1 0 1 Mary A2 0 0 1 Mary A3 1 1 0 Peter A1 1 0 0 Peter A2 0 0 1 Peter A3 1 1 1 Josh A1 1 0 0 Josh A2 Josh A3 0 0 0 I want to convert it into a format where variable rows from a si...

Hi I am having trouble using read.ssd. Can someone help? The code that I have written is *sashome<-"C:/Mary/Datasets"* *read.ssd(read.ssd(file.path(sashome, "core", "sashelp"), "surv_1v",* *sascmd = file.path(sashome, "sas.exe"))* Here the path that I have given is correct, where the dataset surv_1v.sas7bdat is kept. The message that R gives me is this: *SAS...

I have two users on my network, Mary and Bob, who work together in a shared share. They both belong to the group Accounting. Bob is a savvy Linux user who accesses the share via NFS4. Mary toils away using Windows accessing the share via the Samba server. Mary will create a directory on the share and dump a number of files in which Bo...

Hi I have a character vector with thousands of names which looks like this: > V=c("Fred", "Mary", "SAM") > V [1] "Fred" "Mary" "SAM" > class(V) [1] "character" I would like to change it to a list: > L=as.list(V) > L [[1]] [1] "Fred" [[2]] [1] "Mary" [[3]] [1] "SAM" but I need to name the compon...

...quot;01\",\"event_2_arm_1\",\"John\",\"2012-09-02\",\"abc\",\"123\",1\n\"01\",\"event_3_arm_1\",\"John\",\"2012-09-10\",\"\",\"\",2\n\"02\",\"event_1_arm_1\",\"Mary\",\"1951-09-10\",\"def\",\"456\",2\n\"02\",\"event_2_arm_1\",\"Mary\",\"1978-09-12\",\"\",\"\",2\n", "`Content-Type`" = structure(c("text/html", "utf-8"), .Names = c(&qu...

...e not yielded any hints. I have many fields in my dataset that participants entered as "free lists" - i.e., the field constitutes a varying number of names each separated by a delimiter. The resulting data frame might look something like: testtable<- as.data.frame(cbind(c("Joe,Mary,Jane","Mary"),c("Fred,Joe","Pete,Joe,Mary,Fred"))) In actuality the names are typically multi-word organization names, but you get the idea... What I need to do is to convert these text strings into lists comprised of the elements separated by the commas so that...

Hi all, let's say I have matrix People Desc Value Mary Height 50 Mary Weight 100 Fanny Height 60 Fanny Height 200 Is there a quick way to form the following matrix? People Height Weight Mary 50 100 Fanny 60 200 (Assuming I don't know the length of people/desc and let's say these are...

...pink111@yahoo.com> > Hi, > Try this; > library(reshape2) > res<-dcast(Input,people~place,value.var="time") > res[is.na(res)]<-0 > res > # people beach home school sport > #1 Joe 5 3 0 1 > #2 Marc 0 4 2 0 > #3 Mary 0 0 4 0 > > #or > xtabs(time~.,Input) > # place > #people beach home school sport > # Joe 5 3 0 1 > # Marc 0 4 2 0 > # Mary 0 0 4 0 > > A.K. > > > > ________________________________ &...

Hello I have a dataset of people spending time in places. But most people don't hang out in all the places. it looks like: > Input<-data.frame(people=c("Marc","Marc","Joe","Joe","Joe","Mary"), + place=c("school","home","home","sport","beach","school"), + time=c(2,4,3,1,5,4)) > Input people place time 1 Marc school 2 2 Marc home 4 3 Joe home 3 4 Joe sport 1 5 J...

...om the tapply function formatted so that it can be made into a nice table. Below is my question written in R code. Does anyone have any suggestions? Thank you. Geoff #Input the data; name <- c('Tom', 'Tom', 'Jane', 'Jane', 'Enzo', 'Enzo', 'Mary', 'Mary'); year <- c(2008, 2009, 2008, 2009, 2008, 2009, 2008, 2009); group <- c('A', 'A', 'B', 'B', 'A', 'A', 'B', 'B'); class <- c(0, 0, 0, 0, 1, 1, 1, 1); height <- c(62, 63, 59, 58, 67, 66, 70, 71); #Combin...