search for: marital

I have been looking at some 'table' examples in Peter Dalgaard's ISwR book, and I am confused by how to get right justification of my table headings when I use the tables() command. Compare the following: # Produces right justfified column names caff.marital=matrix(c(652,1537,598,242,36,46,38,21,218,327,106,67),nrow=3,byrow=T) colnames(caff.marital)=c("0","1-150","151-300",">300") rownames(caff.marital)=c("Married","Prev.married","Single") caff.marital class(caff.marital) #Produc...

You are missing a comma between "MARITAL" and "JOBSTATUS". On Tue, Apr 10, 2018 at 10:27 AM, Saif Tauheed <saif.tauheed at gmail.com> wrote: > I run this command for converting the numerical variable into factor. > However, I get the following error message. > > > cols<- c(?GrMM", "RELG&q...

Hi everyone, I am just trying to figure out how to do a xyplot where in addition to dots and lines I can change dots' colors according to an individual variable (e.g., marital disruption across time, a dummy 0/1). When I use "groups" specification (see below), I get two different lines for each individual based on groups, and what I want is to get one line connecting dots, and different dots' colors according to marital disruption. Any ideas about how to d...

Dear all, I have a data.frame that includes a series of demographic variables for a set of respondents plus a dependent variable (Theta). For example: Age Education Marital Familysize Income Housing Theta 1: 50 Associate degree Divorced 4 70K+ Owned with mortgage 9.147777 2: 65 Bachelor degree Married 1 10-15K Owned without mortgage 7.345036 3: 33...

Dear Sir/Ma, I Adelabu.A.A, one of the R-users from Nigeria. When am running a coxph command the below error was generated, and have try some idea but not going through. kindly please assist: > cox1 <- coxph(Surv(tmonth,status) ~ sex + age + marital + sumassure, X) Warning message: In fitter(X, Y, strats, offset, init, control, weights = weights, : Ran out of iterations and did not converge > summary(cox1, conf.int=0.95, exact = TRUE) Call: coxph(formula = Surv(tmonth, status) ~ sex + age + marital + sumassure, data = X) n= 595...

Thank you very much. After that I have the following error: cols<- c("GrMM", "RELG", "CASTE1", "SECTOR", "SECTOR4","AGE", "MARITAL", "JOBSTATUS", "ENG", "EDU", "PARENT_EDU", "MASSMEDIA_F", "MASSMEDIA_M", "HomeComputer", "HomeInternet") > for (I in cols) {data.frame[,i]= as.factor(data.frame[,i])} Error in sort.list(y) : 'x' must...

Hi, I see the following is the credit scoreing in R guide : m2<-glm(formula = good_bad ~ checking + duration + history+ purpose +amount + savings + employed + installp + marital + coapp +age + other + depends + telephon + foreign +checking:amount What does checking:amount mean? Regards, Xiaobo Gu

I run this command for converting the numerical variable into factor. However, I get the following error message. > cols<- c(?GrMM", "RELG", "CASTE1", "SECTOR", "SECTOR4","AGE", "MARITAL" "JOBSTATUS", "ENG", "EDU", "PARENT_EDU", "MASSMEDIA_F", "MASSMEDIA_M", "HomeComputer", "HomeInternet") for (i in cols) {data.frame[,i]= as.factor(data.frame[,i])} Error: unexpected string constant in ?cols<-...

...el paquete survival de la ayuda del R funcionan perfectamente ########################################### library(survival) library(epicalc) data(Marryage) use(Marryage) attach(Marryage) summ(Marryage) age <- endyr - birthyr label.var(age, "Age") summ(age, by = marital) age.marr <- maryr - birthyr label.var(age.marr, "Age at marriage") summ(.data[,8:9]) married <- marital == "Married" time <- ifelse(married, age.marr, age) (surv.marr <- Surv(time, married)) head(data.frame(age, age.marr, married, surv.marr)) . c...

What would be a good way to store profile-information, in the cases where the information can be selected from a list of choices? i.e. gender (male,female), religion or marital status. The lists don''t change, so putting that in the db doesn''t seem like a good idea, but how do i put something like this in a model? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on...

Hello, Though Bert's and David's answers are what you should do, note that some R functions that need factors will coerce their input variables when necessary. Have you tried to run the code you haven't posted without coercing to factor? It might run... Hope this helps, Rui Barradas On 4/9/2018 6:11 PM, David L Carlson wrote: > Try the help files: > > ?factor >

Hello everybody. I'm trying to send the result of a decision tree for latex, but I do not get with the package(xtable), there is a package that make this export Export this for latex marital.status = Divorced | educational.num <= 12: <=50K (1795.0/90.0) | educational.num > 12 | | hours.per.week <= 41: <=50K (302.0/58.0) | | hours.per.week > 41 | | | educational.num <= 14: <=50K (160.0/59.0) | | | educational.num > 14: >50K (27.0/4.0...

...l.matrix(coll.1st.formula, data = coll.train) > dim(coll.1st.model.mat) [1] 581618 169 One I saw the resulting model.matrix had fewer rows than the original data.frame I played with the number of input variables in the model: > ttt <- model.matrix(~kmpleasure + vehage + age + gender + marital.status + + license.category + minor.conviction + driver.training.certificate + + admhybrid + anpol + anveh + cie + dblct + faq13c + faq20 + faq27 + faq43 + + faq5a + fra2 + frb2 + frb3 + kmaff + kmannuel + kmtravai + lima + maison + + nacp + nap + nbcond + nbcondpo + nbvt + rabmlt06...

...) >> >> data(Marryage) >> >> use(Marryage) >> >> attach(Marryage) >> >> summ(Marryage) >> >> >> >> >> >> age <- endyr - birthyr >> >> label.var(age, "Age") >> >> summ(age, by = marital) >> >> >> >> age.marr <- maryr - birthyr >> >> label.var(age.marr, "Age at marriage") >> >> summ(.data[,8:9]) >> >> >> >> married <- marital == "Married" >> >> time <- ifelse(married,...

Dear All, My problem is the following > varname <- c("age","sex","edu","mrt") > varstates <- c(10,2,4,3) # 10 age groups, 2 sexes, 4 education group and 3 marital status.. Now, I want four variables (vector with length1) named nrage, nrsex, nredu, nrmrt and assing some values > for (i in 1:4) paste("nr",varname[i],sep="") <- varstates[i] #this does not work I want the following >nrage 10 >nrsex 2 .. etc Thanks in advance...

? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile URL: <https://stat.ethz.ch/pipermail/r-help/attachments/20131104/739bd002/attachment.pl>

...####### > > > > library(survival) > > library(epicalc) > > data(Marryage) > > use(Marryage) > > attach(Marryage) > > summ(Marryage) > > > > > > age <- endyr - birthyr > > label.var(age, "Age") > > summ(age, by = marital) > > > > age.marr <- maryr - birthyr > > label.var(age.marr, "Age at marriage") > > summ(.data[,8:9]) > > > > married <- marital == "Married" > > time <- ifelse(married, age.marr, age) > > > > (surv.marr <- Sur...

Hi: I am using step.glm() as follows: form1 <- as.formula(haspdata ~ 1) lg.mod1 <- glm ( formula=form1, data=st.mtx, family=binomial , na.action=na.omit ) upper <- as.formula( haspdata ~ ( c5+childnm+educ1+incpov1+marital+msa+racekid+racemom+sex+shotcard )^2) lower <- as.formula(haspdata~1) lst <- list( upper=upper , lower=lower ) form1a.step <- step(lg.mod1, scope=lst , trace=T , direction="both" ) I get the following error message in R: Error in factor.scope(ffac, list(add = fadd, drop = fd...

...] "children" "student" "retired" "disabled" "homemaker" "unemployed" "employed" [15] "occupation" "residencysize" "educ" "agemean" "age" "marital" $codepage [1] 1252 > MalesData <- Datatemp[Datatemp $sex==1] > MalesData named list() > attributes(MalesData) $names character(0) Females.Data <- Datatemp[Datatemp $sex==2] *This subset extraction is not working. Is there anyone who can tell me what I did...

I'm using R on Windows v2.0.1 with the nlme package (v3.1-53) and am finding some unexpected discrepancies in the output of intervals.lme and coef.lme. I've included a toy dataset at the end, but briefly, the data are longitudinal data from couples in marital therapy. Each spouse's relationship satisfaction is measured 4 times; I've fit both linear and quadratic models to the change over time. The quadratic fits show the discrpancies. Here's the call to lmList, coef, and intervals: tmp.lis1 <- lmList(dv ~ time + I(time^2)| id/sex, dat...