Displaying 7 results from an estimated 7 matches for "manoranjan".
2013 Oct 31
1
Extracting values from a ecdf (empirical cumulative distribution function) curve
Hi R users,
I am a new user, still learning basics of R. Is there anyway to extract y
(or x) value for a known x (or y) value from ecdf (empirical cumulative
distribution function) curve?
Thanks in advance.
Mano.
[[alternative HTML version deleted]]
2017 Jun 18
3
R_using non linear regression with constraints
...having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Sun, Jun 18, 2017 at 9:43 AM, David Winsemius <dwinsemius at comcast.net> wrote:
>
>> On Jun 18, 2017, at 6:24 AM, Manoranjan Muthusamy <ranjanmano167 at gmail.com> wrote:
>>
>> I am using nlsLM {minpack.lm} to find the values of parameters a and b of
>> function myfun which give the best fit for the data set, mydata.
>>
>> mydata=data.frame(x=c(0,5,9,13,17,20),y = c(0,11,20,29,38,45))...
2017 Jun 18
0
R_using non linear regression with constraints
...on our part, but
not necessarily all the issues.
2) I used nlxb that requires an expression for the model. nlsLM
can use a function because it is using derivative approximations,
while nlxb actually gets a symbolic or automatic derivative if
it can, else squawks.
JN
# Here's the script #
#
# Manoranjan Muthusamy <ranjanmano167 at gmail.com>
#
library(minpack.lm)
mydata=data.frame(x=c(0,5,9,13,17,20),y = c(0,11,20,29,38,45))
myfun=function(a,b,r,t){
prd=a*b*(1-exp(-b*r*t))
return(prd)}
# and using nlsLM
myfit=nlsLM(y~myfun(a,b,r=2,t=x),data=mydata,start=list(a=2000,b=0.05),...
2017 Jun 18
3
R_using non linear regression with constraints
...> 2) I used nlxb that requires an expression for the model. nlsLM
> can use a function because it is using derivative approximations,
> while nlxb actually gets a symbolic or automatic derivative if
> it can, else squawks.
>
> JN
>
> # Here's the script #
> #
> # Manoranjan Muthusamy <ranjanmano167 at gmail.com>
> #
>
> library(minpack.lm)
> mydata=data.frame(x=c(0,5,9,13,17,20),y = c(0,11,20,29,38,45))
>
> myfun=function(a,b,r,t){
> prd=a*b*(1-exp(-b*r*t))
> return(prd)}
>
> # and using nlsLM
>
> myfit=nlsLM(y~myfun(a,b,r=2...
2017 Jun 18
0
R_using non linear regression with constraints
> On Jun 18, 2017, at 6:24 AM, Manoranjan Muthusamy <ranjanmano167 at gmail.com> wrote:
>
> I am using nlsLM {minpack.lm} to find the values of parameters a and b of
> function myfun which give the best fit for the data set, mydata.
>
> mydata=data.frame(x=c(0,5,9,13,17,20),y = c(0,11,20,29,38,45))
>
> myfun=f...
2017 Jun 18
2
R_using non linear regression with constraints
I am using nlsLM {minpack.lm} to find the values of parameters a and b of
function myfun which give the best fit for the data set, mydata.
mydata=data.frame(x=c(0,5,9,13,17,20),y = c(0,11,20,29,38,45))
myfun=function(a,b,r,t){
prd=a*b*(1-exp(-b*r*t))
return(prd)}
and using nlsLM
myfit=nlsLM(y~myfun(a,b,r=2,t=x),data=mydata,start=list(a=2000,b=0.05),
lower = c(1000,0),
2017 Jun 18
0
R_using non linear regression with constraints
...n expression for the model. nlsLM
>> can use a function because it is using derivative approximations,
>> while nlxb actually gets a symbolic or automatic derivative if
>> it can, else squawks.
>>
>> JN
>>
>> # Here's the script #
>> #
>> # Manoranjan Muthusamy <ranjanmano167 at gmail.com>
>> #
>>
>> library(minpack.lm)
>> mydata=data.frame(x=c(0,5,9,13,17,20),y = c(0,11,20,29,38,45))
>>
>> myfun=function(a,b,r,t){
>> prd=a*b*(1-exp(-b*r*t))
>> return(prd)}
>>
>> # and using nls...