search for: maninmoon

How can I generate a vector of differences between each elemtn of an vector? i.e. a[i]=x[i]/x[i-1] -- View this message in context: http://n4.nabble.com/Deltas-or-changes-tp1585960p1585960.html Sent from the R help mailing list archive at Nabble.com.

This does what I was hoping it would: aggregate(tm[,-1],by=list(tm[,10]),FUN="mean") but I don't know what "tm[,-1]" means (well - the -1 bit anyway. Does it somehow means the whole matrix? Please don't tell me to check the manual - I tried and failed dismally... -- View this message in context: http://n4.nabble.com/tm-1-tp1588804p1588804.html Sent from the R

Hi, A number of people have suggested "I read the manuals"... Could someone help me by telling me where the primary start point is please? For example, I am interested in writing functions with variable number of arguments - where should I start to look? "An introduction to R" only show a brief example - with no pointer to where to find further data. I can't do ?xxx

Does anyone know of a gui for R that has "regions" i.e areas of code in a script that can be named and hopefully run as a section? @region Init library(whatever) myprint<-function(...){print(...)} @endregion -- View this message in context: http://n4.nabble.com/GUI-IDE-tp1745858p1745858.html Sent from the R help mailing list archive at Nabble.com.

I have searched and tried to read before posting but can find nothing to accomplish change Excel dates in double format to R Can someone please help I have a vector of double like this from Excel. 39965.0004549653 and I want to put them in R such that I can display them in any Date and Time format. as.Date does it ALMOST but chops off the fractional seconds. POSIXct doesn't appear to do

I have created a large dataframe (d) by getting data from file using read.table I now have 79 columns and 3 million rows. How can I plot the 6th column? I tried plot(d[,6]) but it doesn't look right. When I try to do just d[,6] the console gets some odd "levels" message I don't understand Moon -- View this message in context:

I have a big data frame and I have extracted a bit by doing: > y<-d[1:10,6] > y [1] Headings 0 -49 -98 -49 -41 -120 -155 -204 -169 92329 Levels: -0 -1 -10 -100 -1000 -10000 -10001 -10002 -10003 -10004 -10005 -10006 -10007 -10008 -10009 -1001 -10010 -10011 -10012 -10013 -10014 -10015 -10016 -10017 -10018 -10019 -1002 -10020 -10021 -10022 -10023

I have a matrix with a POSIXct as a numeric in the first column. I would like to create a new matrix that is "grouped by" my chosed time bars. i.e. So I would like to group by hour or day or 5 days, and have all my columns be summed or averaged or counted.. mydata: V1,V2,V3 10:03:13,3.4,1002 10:03:14,5.6,1001 10:05:27,7.2,999 10:05:33,8.2,998 I want to convert this into say 5

How do I get a number representing a date from a POSIXct i.e. removing the time elements? -- View this message in context: http://n4.nabble.com/how-to-return-date-part-of-POSIXct-tp1598109p1598109.html Sent from the R help mailing list archive at Nabble.com.

I am parsing dates as follows: > z[1:10,1:3] V1 V2 V3 1 0 03/02/09 22:20:51.274 2 100 03/02/09 22:28:18.801 3 200 03/02/09 22:33:33.762 4 300 03/02/09 22:40:21.826 5 400 03/02/09 22:41:38.361 6 500 03/02/09 22:42:50.882 7 600 03/02/09 22:45:19.885 8 700 03/02/09 22:48:55.558 9 800 03/02/09 22:51:21.112 10 900 03/02/09 22:58:41.860

...erion (Catherine ENG) > ???9. Transform data set (Thomas Jensen) > ? 10. R-installation regarding. (fredrick devadoss) > ? 11. Re: estimation of parameters with grofit > (alexander russell) > ? 12. Re: Embed R code in C++ (mans) > ? 13. Re: Calling R functions into C# or C++ > (ManInMoon) > ? 14. Re: help with survival package (Shankavaram, Uma > (NIH/NCI) [E]) > ? 15. Re: Transform data set (stephen sefick) > ? 16. Re: Transform data set (Wincent) > ? 17. Re: help with survival package (David > Winsemius) > ? 18. Re: R-installation regarding. (Paul Hiemstra) &...