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males2b
2006 Sep 21
1
survival function with a Weibull dist
...rpreting the outcome and
getting the parameters for each curve.
--------- Value Std. Error z
p
--------- (Intercept) 2.788 0.147 19.022
1.13e-80
--------- males2b -0.107 0.207 -0.519
6.04e-01
--------- males2c -0.486 0.586 -0.831
4.06e-01
--------- males2g 0.580 0.207 2.798
5.15e-03
--------- Log(scale) -1.116 0.139 -8.007
1.18e-15
---------
--------- Scale= 0.328
I know from Venables & Ripley (2002) that the
parameters of this function should be two:
lambda = z (presumably "Value" in R for each
treatment)
alpha =...