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males2b
2006 Sep 21
1
survival function with a Weibull dist
...of this function should be two:
lambda = z (presumably "Value" in R for each
treatment)
alpha = k (scale in R)
Survival function (S):
S(t)= exp-(zt)^k
I don't quite understand how to use the intercept.
First I thought adding it to each other treatment
value, for example:
Survival Males2a (t) = exp ? ((intercept + 0) * t) ^ k
Survival Males2b (t) = exp ? ((intercept + zb)* t) ^ k
But the curves I get using this interpretation are not
similar to my data
Does anyone use this function and could help me to
interpret the results?
many thanks
Anaid