Displaying 14 results from an estimated 14 matches for "mainali".
2018 Feb 23
4
change location of temporary files
...ve in my iMac. This is important because the temporary files R
creates are huge and I do not have enough available space in my internal
HD. Again, this is for macOS.
This change has to be temporary. Later I need to use the usual location for
temp files in the internal HD.
Thanks in advance,
Kumar Mainali
--
Postdoctoral Associate
Department of Biology
University of Maryland, College Park
?
[[alternative HTML version deleted]]
2018 Feb 23
0
change location of temporary files
...1] "/tmp/RTMP-BILL/Rtmppgowz4"
> tempfile()
[1] "/tmp/RTMP-BILL/Rtmppgowz4/file7ce36ec5cb1e"
I don't know if there is an R-specific environment variable or startup
flag for this.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Fri, Feb 23, 2018 at 10:52 AM, Kumar Mainali <kpmainali at gmail.com> wrote:
> I would like to change where R stores the temporary files to my external
> hard drive in my iMac. This is important because the temporary files R
> creates are huge and I do not have enough available space in my internal
> HD. Again, this is for...
2013 Jan 30
2
Programmatically give file name to a matrix
I have a situation when I need to save matrix with file names that are
programmatically created.
for (i in levels(mergeTrn$Continent)) {
matrix here....
# I want to save this matrix with a file name that carries "i" from for
loop. The following does not work.
paste("plotroc_GBM_Trn_", i, sep="") <- matrix
}
Thanks,
Kumar
--
Section of Integrative
2011 Jul 25
2
Selecting unique values
Greetings
I have a dataset with occurrence records of multiple species. I need to get
rid of multiple listings of the same occurrence point for a species (as you
see below in red and blue typeface). How do I create a dataset only with
unique set of longitude and latitude for each species? Thanks in advance.
Species_name Longitude Latitude
Abies concolor -106.601 35.868
Abies concolor -106.493
2017 Dec 07
0
parallel computing with foreach()
...ou may be
inadvertently calling utils::stack which would produce this kind of
error:
> stack(1:25, RAT = FALSE)
Error in data.frame(values = unlist(unname(x)), ind, stringsAsFactors = FALSE) :
arguments imply differing number of rows: 25, 0
HTH,
Peter
On Wed, Dec 6, 2017 at 10:03 PM, Kumar Mainali <kpmainali at gmail.com> wrote:
> I have used foreach() for parallel computing but in the current problem, it
> is not working. Given the volume and type of the data involved in the
> analysis, I will try to give below the complete code without reproducible
> example.
>
> In...
2017 Dec 07
2
parallel computing with foreach()
I have used foreach() for parallel computing but in the current problem, it
is not working. Given the volume and type of the data involved in the
analysis, I will try to give below the complete code without reproducible
example.
In short, each R environment will draw a set of separate files, perform the
analysis and dump in separate folders.
splist <- c("juoc", "juos",
2011 Jan 16
1
Displaying ylab in mfrow
Dear R users,
I cannot display ylab with the following code while trying to stack 7 rows
of 3 histograms each. Thanks in advance!
par(mfrow=c(7,3))
par(mar=c(2,2,2,2))
par(oma=c(5,5,0,0))
with (newdata <- subset(table, Month1 == "1"), hist(newdata$CarapWid,
breaks=5*(0:80), col="gray80", main="All individuals", xlab="", xlim
=c(15,85), ylab="April
2012 Apr 01
1
Selecting files with a particular string in filename
I am trying to find an efficient way to select certain text files from a
folder with thousands of text files. I used file.list function with a
specific "pattern" to obtain 70 files for each of the i's in 1:100. Next, I
need to select some files from this list of 70 files. The files to be
selected do have a unique "pattern" in their file name. However, I cannot
use
2017 Oct 05
0
fraction of null deviance explained by each node/variable in regression trees
...he tree. For instance, at the first split,
this would be (1 - (sum of residual deviance in each of the two
leaves)/deviance at the root). In the subsequent splits, this formula is
slightly different.
There probably is a function to get this done within R. Any help is
appreciated.
Thank you,
Kumar Mainali
--
Postdoctoral Associate
Department of Biology
University of Maryland, College Park
?
[[alternative HTML version deleted]]
2013 Feb 15
1
file copy to password protected network drive
I am trying to copy files to a password protected drive which is "Ranch" at
TACC from another network drive. I am logged in to the source drive and can
run R there. The following code does not even find the destination folder.
file.copy("sourcedrive/file.tar", "
username@ranch.tacc.utexas.edu/uniqueID/destinationfolder/file.tar",
overwrite = FALSE)
Thanks in
2013 Apr 26
1
NMDS in Vegan: problems in stressplot, best solution
Hello,
I can draw a basic stress plot for NMDS with the following code in package
Vegan.
> stressplot(parth.mds, parth.dis)
When I try to specify the line and point types, it gives me error message.
> stressplot(parth.mds, parth.dis, pch=1, p.col="gray", lwd=2, l.col="red")
Error in plot.xy(xy, type, ...) : invalid plot type
In the above code, if I removed line type,
2011 Jan 17
2
How to still processing despite bug errors?
...inding NAs in DF (Ivan Calandra)
> 71. Re: median by geometric mean (S Ellison)
>
>
> ----------------------------------------------------------------------
>
> Message: 1
> Date: Sun, 16 Jan 2011 03:40:40 -0800
> From: Peter Ehlers <ehlers@ucalgary.ca>
> To: Kumar Mainali <kpmainali@gmail.com>
> Cc: "r-help@r-project.org" <r-help@r-project.org>
> Subject: Re: [R] Displaying ylab in mfrow
> Message-ID: <4D32D938.4080908@ucalgary.ca>
> Content-Type: text/plain; charset=ISO-8859-1; format=flowed
>
> On 2011-01-15 18:54, Kum...
2012 Mar 25
2
avoiding for loops
I have data that looks like this:
> df1
group id
1 red A
2 red B
3 red C
4 blue D
5 blue E
6 blue F
I want a list of the groups containing vectors with the ids. I am
avoiding subset(), as it is
only recommended for interactive use. Here's what I have so far:
df1 <- data.frame(group=c("red", "red", "red", "blue",
2012 Apr 06
4
Legend based on levels of a variable
I have a bivariate plot of axis2 against axis1 (data below). I would like
to use different size, type and color for points in the plot for the point
coming from different region. For some reasons, I cannot get it done. Below
is my code.
col <- rep(c("blue", "red", "darkgreen"), c(16, 16, 16))
## Choose different size of points
cex <- rep(c(1, 1.2, 1), c(16, 16,