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Hi, Here i have a file path, for eg : - FPath <- "D:\\MyFolder\\MyFile.txt" HOW IS POSSIBLE TO GET THE FILE NAME FROM THIS GIVEN PATH ? - thanks in advance Antony. -- View this message in context: http://r.789695.n4.nabble.com/Get-the-filename-from-the-given-path-tp4640578.html Sent from the R help mailing list archive at Nabble.com.

Hi, i have a dataframe containing some values. for eg:- MyDataFrame<- Name Age Place ------- ------ ----------- Aby 12 USA Raj 25 UK Romi 32 ENG Amy 31 IND My requirement what is, i have a search key word[it should search from all the columns], that i need to find out from this dataframe. If search keyword found , it

Hi, i have an small doubt. How can we remove serial-number column while writing a dataframe in to a csv file ? for eg:- write.csv(MyDataFrame,"c:/MyData.csv") name place ----------- ----------- 1 antony uk 2 john usa 3 arjun ind here, in the csv file, serial number column is coming extra on the left-end side. i want to remove

Hi here i have a code to split a csv file as per group of line. The code given below, ------------------------------------ SplitCSVByLine <- function(DataMatrix,Destination,NoOfLineToGroup) { input <- file(DataMatrix, "r") fileNo <- 1 repeat { myLines <- readLines(input, n=NoOfLineToGroup) if (length(myLines) == 0) break

Here i have a variable MyVar <- data.frame(read.csv("D:\\Doc.csv")) And now i am storing this variable name into a list. MyList <- list() MyList [length(MyList )+1]<- "MyVar" Now what is the requirement is, i need to call the variable name "MyVar" from the list "MyList " and get the data.

Hi, Here i have an matrix like this, ABC PQR XYZ MNO ------ ------- ------ -------- 3 6 7 15 2 12 24 15 20 5 1 2 25 50 15 35 i need to get the "MODE" - for each column-wise "VARIANCE" - for

Hi, Here in R, I need to load a huge file(.csv) , its size is 200MB. [may come more than 1GB sometimes]. When i tried to load into a variable it taking too much of time and after that when i do cbind by groups, getting an error like this " Error: cannot allocate vector of size 82.4 Mb " My requirement is, spilt data from Huge-size-file(.csv) to no. of small csv files. Here i will give

Hi, May be this helps: ?tb[1,]%*%(((val-rep(meansb79[1,],5))^2)/6) #??????? [,1] #[1,] 1.47619 tryvarb<-c(1,2,3,4,4,4,4) ?var(tryvarb) #[1] 1.47619 tb[2,]%*%(((val-rep(meansb79[2,],5))^2)/6) #???????? [,1] #[1,] 1.904762 sapply(seq_len(nrow(tb)),function(i) tb[i,]%*%(((val-rep(meansb79[i,],5))^2/6))) # [1] 1.4761905 1.9047619 1.9047619 1.9047619 1.9047619 2.2857143 1.9047619 # [8] 1.9047619