Displaying 1 result from an estimated 1 matches for "m_nb".
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m_n
2009 Apr 14
1
mean fold change issues and p values
...m+1
}
n = 1
for(j in col_s2:col_e2){
nb.int.norm[n] <- data.norm.test[i,j]
n <- n+1
}
m_na = mean(na.int.norm, na.rm=TRUE)
m_nb = mean(nb.int.norm, na.rm=TRUE)
mean.na[i] = exp(m_na)
mean.nb[i] = exp(m_nb)
if(group_size[g_1]-sum(is.na(na.int.norm))>1 && group_size[g_2]-sum(is.na(nb.int.norm))>1){
fold.mean[i] = mean.na[i]/mean....