Displaying 1 result from an estimated 1 matches for "m1anova".
2002 Jun 20
2
understanding the output
Hi all,
I try to understand the output of the summary(model).
I make a simple model.
> summary(m1anova)
Call:
glm(formula = peso ~ gen)
Deviance Residuals:
Min 1Q Median 3Q Max
-4.3114 -2.3788 -0.9167 2.1581 5.7856
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 4.8660 0.9808 4.961 0.000101 ***
gen2g 3.8504 1....