search for: lst6

Displaying 4 results from an estimated 4 matches for "lst6".

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2013 Jun 04
0
choose the lines2
...???????????? x4<-x3[!is.na(match(paste(x3$evnmt_brutal,collapse=""),"001")),] ??????????????????????????????????????? x4[!any(duplicated(x4$number))] ??????????????????????????????????????? } ??????????????????????????????????????? )) ??????????????????????????????????? }) ?? lst6<-lst5[lapply(lst5,nrow)!=0] ?? names(lst6)<- unlist(lapply(lst6,function(x) unique(x$patient_id))) ?? Mean_01<-do.call(rbind,lapply(lst6,function(x) cbind(Mean_Middle0=mean(x[seq(nrow(x))%%3==2,"basdai_d"]),Mean_1=mean(x[seq(nrow(x))%%3==0,"basdai_d"])))) rownames(Mean_...
2013 Jun 07
4
matched samples, dataframe, panel data
I R-helpers #I have a data panel of thousands of firms, by year and industry and #one dummy variable that separates the firms in two categories: 1 if the firm have an auditor; 0 if not #and another variable the represents the firm dimension (total assets in thousand of euros) #I need to create two separated samples with the same number os firms where #one firm in the first have a corresponding
2013 Jun 04
0
choose the lines2
...??? ??? ??? x4<-x3[!is.na(match(paste(x3$evnmt_brutal,collapse=""),"001")),] ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? x4[!any(duplicated(x4$number))] ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? } ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? )) ??? ??? ??? ??? ??? ??? ??? ??? ??? }) ?? lst6<-lst5[lapply(lst5,nrow)!=0] ?? names(lst6)<- unlist(lapply(lst6,function(x) unique(x$patient_id))) ?? Mean0bet_01<- do.call(rbind,lapply(lst6,function(x) mean(x[seq(nrow(x))%%3==2,"basdai_d"]))) ?? lst7<-list(lst6,Mean0bet_01) ?? lst7 ?? #lapply(lst7,head,2)??? ?? }?? ??? ???...
2013 Jun 08
0
data
...? lst<- lapply(x,function(y){ ??? ??? ??? ??? ??? ??? ??? y[!all(y$dummy==0),] ??? ??? ??? ??? ??? ??? ??? ???? }) ??? ??? ??? ??? ?? lstNew<- lst[lapply(lst,nrow)>1] ??? ??? ??? ??? ?? lstNew1<- unique(lstNew) ??? ??? ??? ??? ?? }) ???????? lst5<- lst4[lapply(lst4,length)>0] ??? ?lst6<- lapply(lst5,function(x) { ??? ??? ??? ??? ??? lst<- lapply(x,function(y){ ??? ??? ??? ??? ??? ??? ? y[!all(y$dummy==1),] ??? ??? ??? ??? ??? ??? ?? }) ??? ??? ??? ??? ??? lst[lapply(lst,nrow)>0] ??? ??? ??? ??? ??? }) ???????? lst7<- lapply(lst6,function(x){ ??? ??? ??? ??? ??? lst&lt...