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lcall
2013 Mar 12
2
ls() with different defaults: Solution;
...l.names:
http://tolstoy.newcastle.edu.au/R/e6/help/09/03/7588.html
I have struck upon a solution which so far has performed admirably. In particular, it uses ls() and not its explicit source code, so only has a dependency on its name and the name of its all.names argument. Here is my solution:
lsall <- function(...) {
thecall <- as.call(c(as.name('ls'), list(...)))
newcall <- match.call(definition=ls, call=thecall)
if( !('all.names' %in% names(newcall)) ) newcall[['all.names']] <- TRUE
eval(newcall, envir=parent.frame())
}#### end...