Displaying 3 results from an estimated 3 matches for "long3".
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long
2005 Jan 19
1
looking for a basic spatial diff function
...ase: R 2.0.0
editor: GNU Emacs 21.3.2
front-end: ESS 5.2.3
---------------------------------
Colleagues
Is there a function to calculate distances between adjacent latitude/
longitude pairs in a matrix? It is basically a spatial diff() function that
I have in mind.
Data:
long1, lat1
long2, lat2
long3, lat3
looking for: diff(data$long, data$lat)
function Result
long1, lat1
long2, lat2, distance = long/lat2 - long/lat1
long3, lat3, distance = long/lat3 - long/lat2
I've probably missed it but a search of the maillist archives and quick scan
of the packages (map*) did not solve my query. Fo...
2012 Dec 19
1
"For" loop and "if" question
All -
I have a large data frame that looks like
ID p1 p2 p3...p20 Lat1 Lat2 Lat3...Lat20
Long1 Long2 Long3...Long20
1 0 0 1 0 NA NA 29.xx NA
NA NA -89.xx NA
2 1 0 0 1 27.xx NA NA 29.00
-88.00 NA NA -89.xx
3 0 0 0 0 NA NA NA NA
NA NA...
2007 Apr 29
1
randomForest gives different results for formula call v. x, y methods. Why?
...0 0 0.00
versicolor 0 47 3 0.06
virginica 0 5 45 0.10
Any idea why these two should give different results? I can only figure that
the seed, even though it's set, somehow gets altered by the use of a
formula....
> long3.rf<-randomForest(x=iris[,c(1,2,3,4)],y=iris[,5])
> long3.rf
Call:
randomForest(x = iris[, c(1, 2, 3, 4)], y = iris[, 5])
Type of random forest: classification
Number of trees: 500
No. of variables tried at each split: 2
OOB estimate of error rat...