Displaying 1 result from an estimated 1 matches for "lognormaldistribution".
2005 Sep 06
2
(no subject)
...a2,densfun=dweibull,start=list(scale=2 ,shape=1 ))
scale shape
1.378874e+04 8.788857e-01
(3.842224e+03) (1.312395e-01)
> fitdistr(data2,densfun=dweibull,start=list(scale=6 ,shape=2 ))
scale shape
7.81875000 0.12500000
(4.18668905) (0.01803669)
#if i use the lognormaldistribution instead, i would get the same estimates,
#no matter, what starting values i choose.
#or if i tried it so fare with mle(), i got different values depending on the
#starting values too, i use the trial and error method to find appropriate
#starting values, but i am sure, there is a clear way how...