search for: lognorm2

Dear R users, My question is that how it is possible to generate some random numbers using rnorm( ) function but in log transformed values. Thank you, Tobias --------------------------------- [[alternative HTML version deleted]]

...>> dt <- data.frame(sample=sample, bucket=rep(1:nbucket, each = n/nbucket)) >> sample_bucket <- ddply(dt,~bucket,summarise,mean=mean(sample)) >> >> # Función de distribución bucketizada >> dfb <- plnorm(sample_bucket$mean, meanlog = mean, sdlog = sd) >> lognorm2 <- data.frame(sample=sample_bucket$mean, distfun=dfb) >> par(new=TRUE) >> points(lognorm2, col = "blue") >> >> ks.test(lognorm1$sample, lognorm2$sample) # Obtengo p-valor=1 >> >> El problema es que obtengo un p-valor de 1, y creo que debería obtener...

Hello, I am trying to generate random survival times by inverting the function,  S(t)= exp(b*F(t)), where b is constant and F(t) is some cumulative distribution function, let say that F(t) is cdf of normal distribution or any others distributions.   as we know that S(t) has uniform distribution on  (0,1) so we can write that U= exp(b*F(t)), where U is uniform (0,1). Now to generat the time t, we