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en_ca
2006 Jan 25
2
Question about fitting power
...to fit a model y=ax^b.
I know if I made ln(y)=ln(a)+bln(x) this is a linear regression.
But I obtain differente results with nls() and lm()
My commands are: nls(CV ~a*Est^b, data=limiares, start =list(a=100,b=0),
trace = TRUE) for nonlinear regression
and : lm(ln_CV~ln_Est, data=limiares) for linear
regression
Nonlinear regression model: a=738.2238151 and b=-0.3951013
Linear regression: Coefficients:
Estimate Std. Error t value
Pr(>|t|)
(Intercept) 7.8570224 0.0103680 757.8 <2e-16 ***...