search for: lmepblm

Displaying 1 result from an estimated 1 matches for "lmepblm".

2023 Aug 29
1
logLIk(lme(...))?
...hink I should get the same answer as from lm(y~1, ...) within each level of group. I can get the same means, but I don't know how to extract the within-gp standard deviations, and the sum of logLik for the latter two does not equal the former. TOY EXAMPLE: library(nlme) set.seed(1) lmePblm <- data.frame(y=c(rnorm(5, 1, 2), rnorm(5,3,5)), gp=factor(rep(1:2, each=5))) fit22 <- lme(y~gp, lmePblm, random=~1|gp, method='ML') fitGp1 <- lm(y~1, lmePblm[lmePblm$gp==1, ]) fitGp2 <- lm(y~1, lmePblm[lmePblm$gp==2, ]) (ll22 <- logLik(fit22))...