Displaying 1 result from an estimated 1 matches for "lmenocovari".
2010 Aug 05
3
eval-parse and lme in a loop
...8.315122, 12.323612, 14.622557, 11.169847, 10.857631, 14.637243, 7.203096, 7.777472, -1.457673, 2.766380, 9.675148, -5.047292, 1.982447, 3.865502, 5.045913, 10.660579),
c1=rnorm(9, mean=0.1, sd=0.4),
c2=rnorm(9, mean=0.5, sd=0.7),
c3=rnorm(9, mean=0.9, sd=1)
);
## this works
means.lmeNoCovariate=lme(Mean_1 ~ Group, data=df, random = ~ 1 | Subject)
print(summary(means.lmeNoCovariate))
print(anova(means.lmeNoCovariate))
for (meanCol in paste("Mean_", 1:3, sep="")) {
## LMEs go here
cat("######################################################################...