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live
2012 Apr 13
1
Coding columns for survival analysis
...ust found, and "mort" when it was
previously alive but is now dead.
Given the following:
> tree_live = data.frame(tree =
c("tree1","tree2","tree3","tree4","tree5"), live1 = c(0,0,0,1,1), live2
= c(0,0,1,1,0), live3 = c(0,1,1,0,0), live4 = c(1,1,0,0,0), live5 = c(1,
0, 0, 0, 0))
tree live1 live2 live3 live4 live5
1 tree1 0 0 0 1 1
2 tree2 0 0 1 1 0
3 tree3 0 1 1 0 0
4 tree4 1 1 0 0 0
5 tree5 1 0 0 0 0
I w...