search for: liujulia7

Hello, I have a set of data that has a Date column looks like this: 12/9/2007 12/16/2007 1/1/2008 1/3/2008 1/12/2008 etc. I'd like the date to look something like the follow (so that I could sort by date easily). 20071209 20071216 20080101 20080103 20080112 How to do it? Thank you very much Julia -- View this message in context:

Dear R users, I am building a hierarchical model on a large data set. It can take quite some time to finish one fit, I was just wondering whether it is possible to store the fit object (the result) to a file for later (offline) analysis. thanks Julia -- View this message in context: http://www.nabble.com/how-to-store-lme-lmer-fit-result-tp19910951p19910951.html Sent from the R help mailing

Hello, I have a data file (.csv) that has a size of about 2.6 GB. I am not able to read in the whole data set because of the memory limit. I actually only need some columns (3 columns) of the data set, is there a way to read in specified columns? I am using windows. Thanks, Julia -- View this message in context:

Hello, I have a vector: x <- c("A", "A", "A", "B", "A", "A", "C") I'd like to compare each of elements of vector x from its previous element (except for the 1st element which does not have previous element). So I'd like to get a vector y (of same length) that looks something like (0, 0, 0, 1, 1, 0, 1) or (F, F, F,

Hello, I have a data set that looks like this. ID value 111 5 111 6 111 2 178 7 178 3 138 3 138 8 138 7 138 6 . . . I'd like to calculate the mean and var for each object identified by the ID. I can in theory just loop through the whole thing..., but is there a easier way/command which let me calculate the mean/var by ID? Thanks, Julia -- View this

Hello, I have a time series plot drawn using 3 different colored lines, each line corresponds to different category group. I'd like to put legends on the plot. I am using "legend" to do this, however, I can either specify lty or col in legend. Will I be able to do the following in the legend box: a solid black line then g1, a solid red line then g2, a solid blue line then g3?

Dear R users: I am running lmer(), and I had the following warning message: "In mer_finalize(ans): iteration limit reached without convergence (9) What is the default limit for lmer()? And how do I increase the limit? Many thanks, Julia -- View this message in context: http://www.nabble.com/How-to-increase-iteration-limit-for-lmer%28%29--tp20252974p20252974.html Sent from the R help

Dear R users, I need to compare two scatter plots, plot(x1, y1) plot(x2, y2) and would like to plot them in the same figure. How do I do it? Thank you. -- View this message in context: http://www.nabble.com/two-scatter-plots-in-one-tp21963375p21963375.html Sent from the R help mailing list archive at Nabble.com.

Dear R users: I have a data set that looks something like this: ID time y 1 2/01/2008 4 1 2/09/2008 12 1 9/01/2008 8 2 1/06/2008 3 2 3/01/2008 4 2 3/09/2008 9 2 6/03/2008 4 3 1/02/2008 3 3 1/10/2008 8 3 2/02/2008 7 3 2/10/2008 3 I'd like to sum up the weekly data to the monthly level, so that it looks something

...thz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html and provide commented, minimal, self-contained, > reproducible code. ------------------------------ Message: 71 Date: Mon, 29 Sep 2008 13:09:14 -0700 (PDT) From: liujb <liujulia7 at yahoo.com> Subject: [R] quantile To: r-help at r-project.org Message-ID: <19730778.post at talk.nabble.com> Content-Type: text/plain; charset=us-ascii Hello, I need to assign a number to each x[i], i=1:100, based on the value of x[i] and where they are in the distribution of x[i]. F...

Dear R users, I have this vector that consists numeric numbers. Is there a command that detects the repeated numbers in a vector and returns the index of the repeated numbers (or the actual numbers)? For example, v <- c(3,4,5,7,4). The command would return me index 2 and 5 (or the repeated number, 4). Thank you very much, Julia -- View this message in context:

Dear R users, I am running lmer() and having memory problem: "reached total allocation of 1535Mb". The lmer() function was successful (no errors or warnings). However when I do "summary(fit.lmer), I got this "Error: cannot allocate vector of size 19.5 Mb). I used memory.size() and got 1880. I used memory.limit(2500) to increase the memory size to 2500Mb, however I still get

Dear R users: I have a vector of dates as follows: t <- c("2007-01-05", "2007-05-14", "2007-12-28", "2008-01-09", "2008-04-24", "2009-02-14") I'd like to calculate number of days between those dates (time interval). How to do it? Thank you, Julia -- View this message in context:

Dear R users, Suppose I have a vector that consists of characters like ABC, A02, RCA, etc., and there are about 700 of possible characters. For example, x <- c("ABC", "ABC", "ABC", "A02", "ABC", "RCA", "ABC", "ABC") I'd like to get a frequency matrix that looks something like this: ABC 6 A02 1 RCA 1 I

Dear R users, I would like to test the randomness in a series of N values (N>=2). I know that runs.test works for dichotomous factor only: x <- rep(c(1,2), 50) runs.test(factor(x)) However it doesn't work for series that can take any N values (N>2): x <- rep(c(1,2,5,4),50) runs.test(factor(x)) Error in runs.test(factor(x)) : x does not contain dichotomous data Are there any R