Displaying 1 result from an estimated 1 matches for "linearpredictor".
2005 Nov 17
1
Predicting and Plotting "hypothetical" values of factors
...In addition: Warning message:
# variable 'myfac' is not a factor in: model.frame.default(Terms,
newdata, na.action = na.action, xlev = object$xlevels)
# Isn't there an easier way than this?
c1 <- coef(mymod1)
myseq <- seq(0,1, length.out=10)
newdf <- data.frame(1, myseq)
linearPredictor <- as.matrix(newdf) %*% c1
p2 <- 1/ (1 + exp(-linearPredictor))
# But there is a big disaster if you just try the obvious thing
# of plotting with
# lines(myseq,p2)
# The line does not show up where you hope in the plot.
# The plot "appears to" have the x-axis on the scale
# 1.1 to...