search for: lilliefors

...elp me? > > > > Thanks in advance, > > Janete > > The bias of the K-S test with estimated parameters is well known to be > substantial, but I haven't heard about correction terms except (I > think) for the normal distribution. [Dietrich Trenkler] There is a Lilliefors-version of the KS-test for the exponential distribution. See e.g. @ARTICLE{Lilliefors69a, author = {H. W. Lilliefors}, year = 1969, title = {On the {K}olmogorov-{S}mirnov Test for Exponential Distribution with Mean Unknown Variance Unknown}, journal = {Journal of the Ame...

Hi, I use ks.test or lillie.test to verify a normal distribution. It's performed for a group My users use SigmaStat software and a One Way ANOVA on several groups In the result page there is a probability value to determine if Normality test is failed or passed So, how can i retrieve this probability value on several groups? Is there another function in R to verify normality on several

Greetings, We wanted to announce v. 1.4.0 of the R package 'KScorrect', which carries out the Lilliefors correction to the Kolmogorov-Smirnoff (K-S) test for use in (one-sample) goodness-of-fit tests. Aside from several minor changes, the biggest change is that the Monte Carlo algorithm now supports parallel implementation, using the platform-independent 'doParallel' and 'foreach'...

Greetings, We wanted to announce v. 1.4.0 of the R package 'KScorrect', which carries out the Lilliefors correction to the Kolmogorov-Smirnoff (K-S) test for use in (one-sample) goodness-of-fit tests. Aside from several minor changes, the biggest change is that the Monte Carlo algorithm now supports parallel implementation, using the platform-independent 'doParallel' and 'foreach'...

Hi, I'm a newbie and i am unable to use lillie.test in nortest I have a message: "Couldn't find function "lillie.test" I am under windows2000 with R1.8.1 nortest is listed with .packages(TRUE) How to do to use lillie.test function? Laurent Houdusse Analyste Programmeur

Hi, Thakns all for your help I am doing the next in my dataframe tabla, column pend1, because the Lilliefors (Kolmogorov-Smirnov) test give me a pvalue < alfa. (data no normal distribution). I need do a transformation with box-cox or other: > bc <- boxcox.fit(tabla$pend1) R send to me: Error in boxcox.fit(tabla$pend1) : Transformation requires positive data The summary for my data is: > sum...

Hi all, apologies for seeking advice on a general stats question. I ve run normality tests using 8 different methods: - Lilliefors - Shapiro-Wilk - Robust Jarque Bera - Jarque Bera - Anderson-Darling - Pearson chi-square - Cramer-von Mises - Shapiro-Francia All show that the null hypothesis that the data come from a normal distro cannot be rejected. Great. However, I don't think it looks nice to report the values of 8 dif...

...= 3.461e-06 > cvm.test(Mn.Total..ug.kg) Cramer-von Mises normality test data: Mn.Total..ug.kg W = 4.024, p-value = 1.637e+31 > cvm.test(ln.Mn.Total..ug.kg) Cramer-von Mises normality test data: ln.Mn.Total..ug.kg W = 0.356, p-value = 7.647e-05 > lillie.test(Mn.Total..ug.kg) Lilliefors (Kolmogorov-Smirnov) normality test data: Mn.Total..ug.kg D = 0.2325, p-value < 2.2e-16 > lillie.test(ln.Mn.Total..ug.kg) Lilliefors (Kolmogorov-Smirnov) normality test data: ln.Mn.Total..ug.kg D = 0.0869, p-value = 0.002011 OK, next the data column: Mn-Total, ug/kg 460000 400000 5...

...= 3.461e-06 > cvm.test(Mn.Total..ug.kg) Cramer-von Mises normality test data: Mn.Total..ug.kg W = 4.024, p-value = 1.637e+31 > cvm.test(ln.Mn.Total..ug.kg) Cramer-von Mises normality test data: ln.Mn.Total..ug.kg W = 0.356, p-value = 7.647e-05 > lillie.test(Mn.Total..ug.kg) Lilliefors (Kolmogorov-Smirnov) normality test data: Mn.Total..ug.kg D = 0.2325, p-value < 2.2e-16 > lillie.test(ln.Mn.Total..ug.kg) Lilliefors (Kolmogorov-Smirnov) normality test data: ln.Mn.Total..ug.kg D = 0.0869, p-value = 0.002011 OK, next the data column: Mn-Total, ug/kg 460000 400000 5...

...numbers ( it's noise measured with a scoop ) Now i want to know of my data is normal distributed (Gaussian distribution). I did already: - 68-95-99.7 test - Q-Q-plot and now i used "nortest library" and the Lilli.test() However i don't understad the output? lillie.test(z) Lilliefors (Kolmogorov-Smirnov) normality test data: z D = 0.0218, p-value = 0.0278 I read wiki, but still can understand it.. Can anyone, give an explanation of my output D and p-value? Thanks in advance Gr. Bosken -- View this message in context: http://n4.nabble.com/Normal-distribution-Lillie-te...

...> > > gatemaze at gmail.com wrote: > > > > > Hi all, > > > > > > > > > > apologies for seeking advice on a general stats question. I ve run > > > > > > > normality tests using 8 different methods: > > > > > - Lilliefors > > > > > - Shapiro-Wilk > > > > > - Robust Jarque Bera > > > > > - Jarque Bera > > > > > - Anderson-Darling > > > > > - Pearson chi-square > > > > > - Cramer-von Mises > > > > > - Shapiro-Franc...

...me distribution)? Ks.test is not adequate for discrete samples. And, is it possible to use ks.test to test the goodness of fit of a certain given distribution that is not in its list (as it is pnorm, pgamma, ...)? Again I can't estimate any distribution parameter! Is it possible to do a Lilliefors test in R? I couldn't find any of these answers in the literature. Can anyone help me? Alexandra [[alternative HTML version deleted]]

Hello all, Would somebody be kind enough to show me how to do a KS test in R for a lognormal distribution with ESTIMATED parameters. The R function ks.test()says "the parameters specified must be prespecified and not estimated from the data" Is there a way to correct this when one uses estimated data? Regards, Kwabena. -------------------------------------------- Kwabena Adusei-Poku