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Mr/Mrs I am Lili Puspita Rahayu, student from Bogor Agriculture University. I wanna ask that why package ZIGP (Zero inflated Generalized Poisson) is not there anymore? is there any other packages that can analyze ZIGP? I am very grateful for the assistance of R. I am looking forward to hearing from you. Thank yo...

Hi Jim, For true color, I meant that the points in the figure do not correspond to the values from the dataframe. Also, why to use rainbow(9) here? And the legend is straight in the middle, is it possible to reformat it to the very bottom? Thanks again. On Sun, Jul 16, 2017 at 2:50 AM, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi lily, > As I have no idea of what the "true

For more than 10 records, how to reformat the colors? Also, how to show the first legend only, but at the bottom, while the second legend in your code is not necessary? In all, the same A values have the same color, but different symbols in DF==1 and DF==2. Thanks for your help. On Sun, Jul 16, 2017 at 9:28 AM, lily li <chocold12 at gmail.com> wrote: > Hi Jim, > > For true color,

Hi, I have the UPS in subject, it's possible control it with nut ? Sorry for my poor english.

If the OP is using RStudio and not using R (i.e. pdf()) directly, it sounds like this query should be directed to RStudio support, not here. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Sat, Aug 5, 2017 at 5:54 PM, Ismail

In the lower right panel of R-studio interface, there is the "Export" button. I saved as PDF from there directly, rather than using functions On Sat, Aug 5, 2017 at 6:18 PM, Ismail SEZEN <sezenismail at gmail.com> wrote: > > > On 6 Aug 2017, at 03:01, lily li <chocold12 at gmail.com> wrote: > > > > I am using the plot() function, but have a problem.

If layer$z is a matrix and you want to reverse the order of the rows, you can do: n <- nrow(layer$z) layer$z <- layer$z[ n:1, ] HTH, Eric On Tue, Jan 16, 2018 at 8:43 AM, lily li <chocold12 at gmail.com> wrote: > Sorry for the emails, I just wanted to have an example. > layer$z > > 1 1 3 4 6 2 > 2 3 4 1 2 9 > 1 4 5 2 1 8 > > How to convert

On 05/08/2017 9:10 PM, Bert Gunter wrote: > If the OP is using RStudio and not using R (i.e. pdf()) directly, it > sounds like this query should be directed to RStudio support, not > here. Two things: First, to Lily: "?" is the "per mil" symbol, not percent; it's not an ASCII symbol, which is why there are issues displaying it. If you really mean percent, use

Hi Bert, I think you are correct that I can use levelplot, but I have a question about converting data. For example, the statement: levelplot(Z~X*Y), Z is row-wise from the lower left corner to the upper right corner. My dataset just have gridded Z data as a txt file (or can be called matrix?), how to convert them to the vector in order for levelplot to use? Thanks. On Mon, Jan 15, 2018 at 6:04

Sorry for the emails, I just wanted to have an example. layer$z 1 1 3 4 6 2 2 3 4 1 2 9 1 4 5 2 1 8 How to convert the matrix to layer$z = c(1, 4, 5, 2, 1, 8, 2, 3, 4, 1, 2, 9, 1, 1, 3, 4, 6, 2)? I think this vector is the order that levelplot can use. Thanks again. On Mon, Jan 15, 2018 at 10:58 PM, lily li <chocold12 at gmail.com> wrote: > Hi Bert, > > I think

Hi R users, Could you help me to see this problem? I could now load "rgdal" even though I downloaded the compressed folder. Thanks for your help. Loading required package: sp Error in dyn.load(file, DLLpath = DLLpath, ...) : unable to load shared object '/Library/Frameworks/R.framework/Versions/3.3/Resources/library/rgdal/libs/rgdal.so': [[alternative HTML version deleted]]

Hi Lily, lily li <chocold12 at gmail.com> writes: > Hi R users, > > Could you help me to see this problem? I could now load "rgdal" even though > I downloaded the compressed folder. Thanks for your help. > > Loading required package: sp > Error in dyn.load(file, DLLpath = DLLpath, ...) : > unable to load shared object >

> On 6 Aug 2017, at 03:47, lily li <chocold12 at gmail.com> wrote: > > In the lower right panel of R-studio interface, there is the "Export" button. I saved as PDF from there directly, rather than using functions > > On Sat, Aug 5, 2017 at 6:18 PM, Ismail SEZEN <sezenismail at gmail.com> wrote: > > > On 6 Aug 2017, at 03:01, lily li <chocold12 at

Hi all, I ran the code: > s <- stack(replicate(2, raster(matrix(runif(100), 10)))) > xy <- data.frame(coordinates(sampleRandom(s, 10, sp=TRUE)), + z1=runif(10), z2=runif(10)) > levelplot(s, margin=FALSE, at=seq(0, 1, 0.05)) + + layer(sp.points(xy, pch=ifelse(pts$z1 < 0.5, 2, 3), cex=2, col=1), columns=1) + + layer(sp.points(xy, pch=ifelse(pts$z2 < 0.5, 2,

Hi Ulrik, Thanks for your suggestion, but it was not what I meant. I tried to use the rPref package but just got a very small sample and felt clueless. On Sat, Aug 26, 2017 at 12:37 AM, Ulrik Stervbo <ulrik.stervbo at gmail.com> wrote: > HI lily, > > for the colouring of individual points you can set the colour aesthetic. > The ID is numeric so ggplot applies a colour scale.

Hi all, I'm trying to add single points with known coordinates to a level plot, but could not find the proper answer. I got to know that layer() function is good for this, but I don't know which package is related to this function. The source is here: https://stackoverflow.com/questions/28597149/add-xy-points-to-raster-map-generated-by-levelplot but my question is a little different as I

Hi lily, You can get fairly good starting values just by eyeballing the curves: plot(y) lines(supsmu(1:20,y)) lines(0.6*cos((1:20)/3+0.6*pi)+17.2) Jim On Wed, Jun 21, 2017 at 9:17 AM, lily li <chocold12 at gmail.com> wrote: > Hi R users, > > I have a question about fitting a cosine curve. I don't know how to set the > approximate starting values. Besides, does the method

Thanks, Jim. The code works, but I don't understand why you use q1090 <- quantile(DF1$B, probs=c()), rather than DF1$A? Also, how to add a legend for both points DF1 and DF2? On Wed, Jul 12, 2017 at 8:25 PM, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi lily, > Here is the first plot: > > plot(DF1$A,DF1$B,pch=19,col="red") > meanA<-mean(DF1$A) >

Hi R users, I have a question about fitting a cosine curve. I don't know how to set the approximate starting values. Besides, does the method work for sine curve as well? Thanks. Part of the dataset is in the following: y=c(16.82, 16.72, 16.63, 16.47, 16.84, 16.25, 16.15, 16.83, 17.41, 17.67, 17.62, 17.81, 17.91, 17.85, 17.70, 17.67, 17.45, 17.58, 16.99, 17.10) t=c(7, 37, 58, 79, 96,

You need to load the package 'rasterVis' > library(rasterVis) HTH, Eric On Thu, Mar 8, 2018 at 5:11 PM, lily li <chocold12 at gmail.com> wrote: > Hi all, > > I ran the code: > > s <- stack(replicate(2, raster(matrix(runif(100), 10)))) > > xy <- data.frame(coordinates(sampleRandom(s, 10, sp=TRUE)), > + z1=runif(10), z2=runif(10))